A vertical equal-tangent, 100O ft long, connects an initial grade of -2.5% and a final grade of +2%. The PVC of the curve is located at station 95 + 00 and has an elevation of 850 ft. At which station is the PVI of the curve located? 80 + 00 O 83 + 75

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A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

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Q: A +0.7% grade meets a -0.4% grade at sta 2+700 and at elevation 30 m. The max allowable change in…

A: Given information, n1 = 0.7%n2 = -0. 4%Maximum allowable change in grade/sta.=0.2%

Q: only need 23.2 PROBLEMS 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line…

A: The given data is shown below: Length of curve=700 ftFirst grade=4.2%Second…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

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A: Length of curve (L) = 400 ftStation of PVC = 78+00Elevation of PVC = 800 ft

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Q: a crest vertival curve connects a +4.44% grade and a -6.87% grade. The PVI is at station 43 + 15.25…

A: Hi there!! since you have posted a question with multiple subparts, we will solve the first three…

Q: A 600 ft equal tangent vertical The initial grade is -3.5% and the final grade is +0.5%. Determine…

A: L=600ft

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Q: 7. A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance…

A: jkjethgnfjhjjj

Q: 1. An equal-tangent crest vertical curve is being designed connects grades of 1.3% and -2.4% in the…

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