A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of 950.00', and a PVI station of 150+25 and elevation of 1005.22'. Determine: (a) the elevation and stationing of the PVC and PVT; (b) the elevation of the curve at station 154+55.00; and (c) the elevation and stationing of the highest and lowest points on the curve? Report all answers to the nearest 0.01 ft. Just need part C explained please

Q: An incoming grade of +1.800% meets an exiting grade of -2.500% at a PVI having station = 27+32.20…

A: Incoming grade = +1.800% Exiting grade = -2.500% PVI station = 27+32.20 PVI elevation = 231.87…

Q: answer question 18 only

A:

Q: 19. What is the stationing (ft) of the EVC?

A: Length of curve, L = 1100ft  ⇒ 11 stations.   Stationing of BVC = 12+15 ft.

Q: have designed a vertical crest curve which joins a +3% E mph and you have determined the curve to be…

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Q: Question # 5 An existing crest vertical curve which connects +3% and -1% grades is designed for 55…

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Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: On a vertical alignment a +10 % grade (back tangent) meets a -4% grade (forward tangent) at station…

A: Initial grade, G1 = 10%Final grade, G2 = -4%Length of the curve, L = 1000 ftElevation of PVC, e =…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

A: Given: The station of lower point A is 55+50. The elevation of A is 1291.2 m. The back grade is -6%.…

Q: 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line and a-4.0% grade line.…

A: The length of curve, L= 1500 ftThe grade of upgrade, g1 = +3%The grade of downgrade, g2 = -4%The…

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

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Q: you have determined the curve to be 1100 ft long. Now, you need to when the BVC is located at…

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Q: A vertical curve of 1,000-ft is designed to connect a grade of +4% to a grade of -5%. The V.P.I, is…

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Q: A vertical equal-tangent, 100O ft long, connects an initial grade of -2.5% and a final grade of +2%.…

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Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: 1. An equal-tangent crest vertical curve is being designed connects grades of 1.3% and -2.4% in the…

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Q: 1. A vertical parabolic summit curve was designed in order to have a clear sight distance of 120m.…

A: Sight Distance= 120 mGrade lines intersection :Station = 9+00Elevation = 160.50 mHeight of driver's…

Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.