only need 23.2 PROBLEMS 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line and a -4.0% grade line. The vertex or intersection of the grade lines is at station 57+00 and the elevation there is 583.25 ft. Compute the elevations at 100-fi stations throughout the curve. ood (Ans.: Curve elevation at station 53, 55, and 59 = 568.39 ft, 570.19 ft, 568.19 ft 23.2 Repeat Problem 23.1 if the curve is 700 ft long and the first grade is +4.2% instead of +3.0%.
only need 23.2 PROBLEMS 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line and a -4.0% grade line. The vertex or intersection of the grade lines is at station 57+00 and the elevation there is 583.25 ft. Compute the elevations at 100-fi stations throughout the curve. ood (Ans.: Curve elevation at station 53, 55, and 59 = 568.39 ft, 570.19 ft, 568.19 ft 23.2 Repeat Problem 23.1 if the curve is 700 ft long and the first grade is +4.2% instead of +3.0%.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:only need 23.2
PROBLEMS
23.1 A 1,500-ft vertical curve is to be used for joining a
+3.0% grade line and a -4.0% grade line. The vertex or
intersection of the grade lines is at station 57 + 00 and the
elevation there is 583.25 ft. Compute the elevations at 100-i
stations throughout the curve.
i0oxd (Ans.: Curve elevation at station
53, 55, and 59 = 568.39 ft, 570.19 ft, 568.19 ft
23.2 Repeat Problem 23.1 if the curve is 700 ft long and the
first grade is +4.2% instead of +3.0%.
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