I need assitance with solving Chapter 10 Question 11. I made numerous attempts to solve. however I am still having issues. Please provide a step by step explanation so, I can use it as notes for future reference. Respectfully thank you. II. An engineering firm retains a technical specialist to assist four design engineers working on a project. The help that the specialist givesengineers ranges widely in time consumption. The specialist has some answers available in memory, others require computation, andstill others require significant search time. On average, each request for assistance takes the specialist one hour.The engineers require help from the specialist on the average of once each day. Because each assistance takes about an hour, eachengineer can work for seven hours, on average, without assistance. One further point: Engineers needing help do not interrupt if thespecialist is already involved with another problem.Treat this as a finite queuing problem and answer the following questions:a. How many engineers, on average, are waiting for the technical specialist for help?b. What is the average time an engineer has to wait for the specialist?c. What is the probability an engineer will have to wait in line for the specialist?

Based on the question description, the following information is extracted. Number of design engineers (Customers) (N)= 4 Number of technical specialists (S)= 1 Time required for service (T) = 1 hour Average time engineer can work without assistance (U) = 7 hrsX = TT+U=11+7=18=0.125 Use the table given below to get the value of F. For X = 0.125 and S =1, F = 0.945 L = N1-F = 4(1-0.945)=0.22 engineersW = L(T+U)N-L=0.22(1+7)4-0.22=0.22×83.78=0.465608 hrsThe probability that an engineer has to wait is in the table given in step 2. Read off D for it. The probability that an engineer has to wait for the specialist is 0.362.