An electron moves with speed 2.00 × 105 m/s in a 1.90-T uniform magnetic field. At one instant, the electron is moving due west and experiences an upward magnetic force of 3.50 × 10−14 N. Which of the following is the correct direction of magnetic field? (If there is more than one po
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Module 4 Question 11:
An electron moves with speed 2.00 × 105 m/s in a 1.90-T uniform magnetic field. At one instant, the electron is moving due west and experiences an upward magnetic force of 3.50 × 10−14 N. Which of the following is the correct direction of magnetic field? (If there is more than one possible answer, find all the possibilities.)
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- a) Write an equation for the magnetic force experienced by an electron travelling in a uniform magnetic field. Determine each term used in the equation. b) A electron travels with speed 8.8x105 m/s in a uniform magnetic field of magnetic field strength 10-4 T. The electron traces a circular path with the magnetic force acting as the centripetal force. Determine the radius of the circular path of the electron? [Assume mass of electron = 9.1 x 10-31 kg, charge of electron = -1.6 × 10-1⁹ C]A long straight wire carries a 1.5 A current. An electron moves parallel to the wire at speed 1.3 x 104 m/s. The distance between the electron and the wire is 7 cm. Calculate the magnitude of the magnetic force on the electron.A proton moving at 4.50 x 106 m/s through a magnetic field of magnitude 1.68 T experiences a magnetic force of magnitude 8.40 x 10-13 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest.)
- After being accelerated to a speed of 1.92×105 m/s , the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 34.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb.A particle of mass m=3.1×10−5kg and charge q=43μC moves with a velocity v⃗ =−2.1×104ms−1 i^ along the x axis. a) Find the magnitude of magnetic field created by this charged particle at a distance d=37cm from the x axis. Draw a schematic diagram. b) Now, if the charged particle moves in an uniform external magnetic field, B⃗ =−3.8T k^ , then calculate the magnetic force experienced by the charged particle in unit vector notation. x component of the magnetic force y component of the magnetic force z component of the magnetic force c) What will be the shape of the path of the charged particle moving in the uniform external magnetic field. Draw a schematic diagram and calculate a geometric quantity that can help you explain the path. d) Along with the external magnetic field, if we now apply an external electric field on the charged particle in a particular direction - the particle moves in a stright line. Explain why. And calculate the external electric field in unit vector notation.…A singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T. (Note that the charge of an electron is e = 1.6 x 10−19 C.) a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?
- The earth's magnetic field can affect the electron beam in an oscilloscope or a television tube. An electron that has been accelerated through a potential difference of 5.03 104 V has a horizontal initial velocity, directed north. Find the magnetic force on the electron when the earth's field has a horizontal component of 0.250 G and dips 60.0° below the horizontal (values typical in California). Magnitude ______ Direction _______A proton moving at 4.30 x 10° m/s through a magnetic field of magnitude 1.62 T experiences a magnetic force of magnitude 8.80 x 105 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest.)A proton is moving along in the +y-direction with a speed of 5.2 × 105 m/s experiences a magnetic force of 8.5 × 10−4 N out of the page. A second proton moves along in the −x-direction at the same speed but experiences no magnetic force. What is the strength and direction of the magnetic field?[Answer: B⃗ = −1.0 × 1010 T xˆ]
- An electron moves in a uniform circular motion under the action of an external magnetic field. -19 Consider the charge of the electron 9 = -1.6 × 10- v = 2.8 X 107 [C], the speed of the electron B = 2.1 x 10-³ [m/s] and the magnitude of the external magnetic field [T]. Calculate the radius R of the circle formed by the electron during its displacement. Write your answer in centimeters and round to the first decimal.A proton is propelled at 4××1066 m/s perpendicular to a uniform magnetic field. 1)If it experiences a magnetic force of 4.8×10−13 N, what is the strength of the magnetic field? (Express your answer using two significant figures.)A proton moving at 4.80 x 106 m/s through a magnetic field of magnitude 1.76 T experiences a magnetic force of magnitude 7.00 × 10-¹3 N. What is the angle between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between 0 and 360.) smaller value larger value O O