A singly charged ion (q= 1.6 × 10-19 C, mass m = 2.2 x 10-27 kg) moving with speed v6.5 x 106 m/s enters a region of a uniform magnetic field B = 0.040 T. Its path of travel is shown in the figure below. A) Determine the magnetic force (magnitude and direction) acting on the ion at the instant of time when it enters the magnetic field. B) Calculate the radius of the semicircular path of the ion. Show calculations (derive the formula for the radius). x x X x X X X X X X
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- A particle with charge 0.350 C is initially traveling at 90.0 m/s along the +y-direction and encounters a magnetic field of 1.30x10-2 T along the +x-direction. Part A What is the magnitude of the force on the charge? n ΑΣφ ? F = N Submit Request Answer Part B What is the direction of the force? O +x direction -x direction +y direction O -y direction +z direction O -z direction O O O O O CI Review Part C A0.32 µC particle moves with a speed of 18 m/s through a region where the magnetic field has a strength of 0.99 T. You may want to review (Pages 773 - 777). At what angle to the field is the particle moving if the force exerted on it is 1.0 x 10-'N? Express your answer using two significant figures. | O You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Request AnswerA single ionized atom, that is deficient one electron, is traveling at in a straight line when it enters a uniform magnetic field of strength 0.750 T. The ion is traveling in the plane of the page, while the magnetic field points into the page. (See the diagram below.) If the mass of the ionized atom is 6.68 x 10-27 kg, what is the frequency in Hz of the resultant circular motion? The charge of a single electron is 1.602 x 10-19 C. a. 7.47 MHz b. 6.33 MHz c. 4.13 MHz d. 3.50 MHz e. .2.86 MHz
- The magnetic field in a hospital’s cyclotron is 0.170 T. Find the magnitude of the magnetic force on a proton with speed 2.60 × 107 m/s moving in a plane perpendicular to the field. answer in NA particle of mass m=3.1×10−5kg and charge q=43μC moves with a velocity v⃗ =−2.1×104ms−1 i^ along the x axis. a) Find the magnitude of magnetic field created by this charged particle at a distance d=37cm from the x axis. Draw a schematic diagram. b) Now, if the charged particle moves in an uniform external magnetic field, B⃗ =−3.8T k^ , then calculate the magnetic force experienced by the charged particle in unit vector notation. x component of the magnetic force y component of the magnetic force z component of the magnetic force c) What will be the shape of the path of the charged particle moving in the uniform external magnetic field. Draw a schematic diagram and calculate a geometric quantity that can help you explain the path. d) Along with the external magnetic field, if we now apply an external electric field on the charged particle in a particular direction - the particle moves in a stright line. Explain why. And calculate the external electric field in unit vector notation.…A singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T. (Note that the charge of an electron is e = 1.6 x 10−19 C.) a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?