See the attached figure for this problem. A charge of 9.93 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 1.09 T directed into the screen and an electric field of strength 1.95 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed? 1.43E+05 m/s 8.95E+04 m/s 1.79E+04 m/s 1.79E+05 m/s **Figure 1: Explanation for Educational Use**This diagram illustrates a scenario involving electric and magnetic fields, commonly used in physics problems. - **X's and B Field**: The background is filled with "X" marks, indicating a magnetic field (denoted as B) that points into the plane of the diagram.- **E Field**: There are vertical arrows pointing downward labeled as E, representing an electric field.- **Particle and Velocity**: A dot represents a charged particle moving with velocity v, shown by the arrow pointing to the right. - **Forces on the Particle**: - **Fe**: The force due to the electric field is labeled as Fe, pointing downward, in the same direction as the electric field. - **Fm**: The force due to the magnetic field is labeled as Fm, pointing upward, resulting from the cross product of the velocity vector v and the magnetic field B.This setup is typical for examining the effects of electric and magnetic forces on a charged particle, often used to demonstrate the concept of the Lorentz force.

Answered: See the attached figure for this…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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See the attached figure for this problem. A charge of 9.93 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 1.09 T directed into the screen and an electric field of strength 1.95 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed?

	1.43E+05 m/s
	8.95E+04 m/s
	1.79E+04 m/s
	1.79E+05 m/s

**Figure 1: Explanation for Educational Use**

This diagram illustrates a scenario involving electric and magnetic fields, commonly used in physics problems.

- **X's and B Field**: The background is filled with "X" marks, indicating a magnetic field (denoted as B) that points into the plane of the diagram.

- **E Field**: There are vertical arrows pointing downward labeled as E, representing an electric field.

- **Particle and Velocity**: A dot represents a charged particle moving with velocity v, shown by the arrow pointing to the right.

- **Forces on the Particle**:
- **Fe**: The force due to the electric field is labeled as Fe, pointing downward, in the same direction as the electric field.
- **Fm**: The force due to the magnetic field is labeled as Fm, pointing upward, resulting from the cross product of the velocity vector v and the magnetic field B.

This setup is typical for examining the effects of electric and magnetic forces on a charged particle, often used to demonstrate the concept of the Lorentz force.

Expert Solution

Step 1: Electric force and magnetic force

Since the charge is moving at a constant velocity, the net force on the charge will be zero.

Write the expression for the net force and substitute the corresponding expressions to obtain the expression for the speed of the charge.

$table row cell F equals F subscript E plus F subscript B end cell row cell m a with rightwards arrow on top equals q E with rightwards arrow on top plus q left parenthesis v with rightwards arrow on top cross times B with rightwards arrow on top right parenthesis end cell row cell m left parenthesis 0 right parenthesis equals q E minus q v B end cell row cell v equals E over B end cell end table$

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