7. A negatively charged particle (q = -25.0μC) travels at a constant speed of 2.65 x 106 m/s into this page. It thenenters a uniform magnetic field of magnitude 4.50 x 105 T that points towards the left of this page.a) What is the maximum magnitude of the magnetic force?Nb) What is the direction of the magnetic force?towards the left of this pagetowards the bottom of this pagetowards the right of this pageout of this pageinto this pagetowards the top of this pageOоо

7 a)=magnetic force=charge of moving particle=particle velocity=magnetic field=angle between…

Answered: 7. A negatively charged particles…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

7. A negatively charged particle (q = -25.0μC) travels at a constant speed of 2.65 x 106 m/s into this page. It then
enters a uniform magnetic field of magnitude 4.50 x 105 T that points towards the left of this page.
a) What is the maximum magnitude of the magnetic force?
N
b) What is the direction of the magnetic force?
towards the left of this page
towards the bottom of this page
towards the right of this page
out of this page
into this page
towards the top of this page
O
оо

Expert Solution

Step 1: Magnetic Force

7 a)

$F=q v B \sin \theta$

	=	magnetic force
	=	charge of moving particle
	=	particle velocity
	=	magnetic field
$\theta$	=	angle between velocity and magnetic field vectors

(a)

The maximum magnitude of the magnetic force is,

$F equals negative q subscript e v B$

Here, the negative sign indicates the magnetic field points left of the page.

Substitute the values.

$table row F equals cell negative open parentheses negative 25 cross times 10 to the power of negative 6 end exponent space text C end text close parentheses open parentheses 2.65 cross times 10 to the power of 6 space text m/s end text close parentheses open parentheses 4.50 cross times 10 to the power of 5 space text T end text close parentheses end cell row blank equals cell space 14.7 cross times 10 to the power of negative 5 end exponent space text N end text end cell row cell open vertical bar F close vertical bar end cell equals cell 2.98 cross times 10 to the power of 7 space text N end text end cell end table$

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