A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 6.33 × 10−¹6 N as it moves at 217 m/s at 69.7° to the direction of the field. Find the magnitude of the magnetic field. T

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of
6.33 × 10-¹6 N as it moves at 217 m/s at 69.7° to the direction of the field. Find the magnitude of the magnetic field.
T
Transcribed Image Text:A doubly ionized molecule (i.e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 6.33 × 10-¹6 N as it moves at 217 m/s at 69.7° to the direction of the field. Find the magnitude of the magnetic field. T
Expert Solution
Step 1: Given

Given
M a g n e t i c space f o r c e space straight F subscript straight m equals 6.33 cross times 10 to the power of negative 16 end exponent space straight N
straight v equals 217 space straight m divided by straight s
straight theta equals 69.7 degree

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