1. A proton is entering magnetic field B 0.2 i-0.5 j+ 0.4 k. If the proton moves at v (4000i + 5000 k) in meters per second, find the force vector acting on the proton. Proton charge is 1.6 x 10 C a. F = (4000 i + 960 j -3200 k) x 1019 N c. F = (4000 i – 960 j -3200 k) x 10-19 N. b. F = (4000 i - 960 j+3200 k) x 1019 N d. F = (4000 i + 960 j +3200 k) x 10-19 N

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Question 1 and 2

### Physics Problems Involving Magnetic Fields and Charged Particles

1. **Problem 1: Force on a Proton in a Magnetic Field**
   
   A proton is entering a magnetic field \( \mathbf{B} = 0.2 \, \mathbf{i} - 0.5 \, \mathbf{j} + 0.4 \, \mathbf{k} \). If the proton moves at \( \mathbf{v} = (4000 \, \mathbf{i} + 5000 \, \mathbf{k}) \) m/s, find the force vector acting on the proton. The charge of the proton is \( 1.6 \times 10^{-19} \, \text{C} \).

   - a. \( \mathbf{F} = (4000 \, \mathbf{i} + 960 \, \mathbf{j} - 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
   - b. \( \mathbf{F} = (4000 \, \mathbf{i} - 960 \, \mathbf{j} + 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
   - c. \( \mathbf{F} = (4000 \, \mathbf{i} - 960 \, \mathbf{j} - 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
   - d. \( \mathbf{F} = (4000 \, \mathbf{i} + 960 \, \mathbf{j} + 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)

2. **Problem 2: Charge Magnitude for a Charged Body in a Magnetic Field**

   A charged body, moving with a velocity of \( 8.0 \times 10^4 \, \text{m/s} \) at an angle of 30 degrees with respect to the magnetic field of strength \( 5.6 \times 10^{-5} \, \text{T} \), experiences a force of \( 0.00002 \, \text{N} \). What is the magnitude of the charge?

   - a. \( 8.9 \
Transcribed Image Text:### Physics Problems Involving Magnetic Fields and Charged Particles 1. **Problem 1: Force on a Proton in a Magnetic Field** A proton is entering a magnetic field \( \mathbf{B} = 0.2 \, \mathbf{i} - 0.5 \, \mathbf{j} + 0.4 \, \mathbf{k} \). If the proton moves at \( \mathbf{v} = (4000 \, \mathbf{i} + 5000 \, \mathbf{k}) \) m/s, find the force vector acting on the proton. The charge of the proton is \( 1.6 \times 10^{-19} \, \text{C} \). - a. \( \mathbf{F} = (4000 \, \mathbf{i} + 960 \, \mathbf{j} - 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \) - b. \( \mathbf{F} = (4000 \, \mathbf{i} - 960 \, \mathbf{j} + 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \) - c. \( \mathbf{F} = (4000 \, \mathbf{i} - 960 \, \mathbf{j} - 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \) - d. \( \mathbf{F} = (4000 \, \mathbf{i} + 960 \, \mathbf{j} + 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \) 2. **Problem 2: Charge Magnitude for a Charged Body in a Magnetic Field** A charged body, moving with a velocity of \( 8.0 \times 10^4 \, \text{m/s} \) at an angle of 30 degrees with respect to the magnetic field of strength \( 5.6 \times 10^{-5} \, \text{T} \), experiences a force of \( 0.00002 \, \text{N} \). What is the magnitude of the charge? - a. \( 8.9 \
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