1. A proton is entering magnetic field B 0.2 i-0.5 j+ 0.4 k. If the proton moves at v (4000i + 5000 k) in meters per second, find the force vector acting on the proton. Proton charge is 1.6 x 10 C a. F = (4000 i + 960 j -3200 k) x 1019 N c. F = (4000 i – 960 j -3200 k) x 10-19 N. b. F = (4000 i - 960 j+3200 k) x 1019 N d. F = (4000 i + 960 j +3200 k) x 10-19 N
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
Question 1 and 2
![### Physics Problems Involving Magnetic Fields and Charged Particles
1. **Problem 1: Force on a Proton in a Magnetic Field**
A proton is entering a magnetic field \( \mathbf{B} = 0.2 \, \mathbf{i} - 0.5 \, \mathbf{j} + 0.4 \, \mathbf{k} \). If the proton moves at \( \mathbf{v} = (4000 \, \mathbf{i} + 5000 \, \mathbf{k}) \) m/s, find the force vector acting on the proton. The charge of the proton is \( 1.6 \times 10^{-19} \, \text{C} \).
- a. \( \mathbf{F} = (4000 \, \mathbf{i} + 960 \, \mathbf{j} - 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
- b. \( \mathbf{F} = (4000 \, \mathbf{i} - 960 \, \mathbf{j} + 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
- c. \( \mathbf{F} = (4000 \, \mathbf{i} - 960 \, \mathbf{j} - 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
- d. \( \mathbf{F} = (4000 \, \mathbf{i} + 960 \, \mathbf{j} + 3200 \, \mathbf{k}) \times 10^{-19} \, \text{N} \)
2. **Problem 2: Charge Magnitude for a Charged Body in a Magnetic Field**
A charged body, moving with a velocity of \( 8.0 \times 10^4 \, \text{m/s} \) at an angle of 30 degrees with respect to the magnetic field of strength \( 5.6 \times 10^{-5} \, \text{T} \), experiences a force of \( 0.00002 \, \text{N} \). What is the magnitude of the charge?
- a. \( 8.9 \](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F366fde98-e986-4900-b8c3-3945c69e5ca7%2F56bf8909-91a4-405d-a13b-a732482498e2%2Fg0adpzf_processed.jpeg&w=3840&q=75)
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