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An electron moves with a speed of \(5.0 \times 10^4\) m/s perpendicular to a uniform magnetic field of magnitude 0.20 T. What is the magnitude of the magnetic force on the electron? (\(e = 1.60 \times 10^{-19}\) C).

Hint:

\[ \vec{F} = q(\vec{V} \times \vec{B}) = qVB \sin \theta, \text{ where } \theta \text{ is the angle between the direction of the } B \text{ and } V \]

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