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A particle of mass 11.3 g and charge 91.5 µC moves through a uniform magnetic field, in a region where the free-fall acceleration is -9.8 m/s² without falling. The velocity of the particle is a constant 23.81 km/s, which is perpendicular to the magnetic field. What, then, is the magnetic field? Number ( i + i 0 k) Units mT Ĵ +

A particle of mass 11.3 g and charge 91.5 µC moves through a uniform magnetic field, in a region where the free-fall acceleration is -9.8 m/s² without falling. The velocity of the particle is a constant 23.81 km/s, which is perpendicular to the magnetic field. What, then, is the magnetic field? Number ( i + i 0 k) Units mT Ĵ +

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Problem: Determining the Magnetic Field** A particle of mass 11.3 g and charge 91.5 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is -9.8 \( \hat{\jmath} \) m/s\(^2\) without falling. The velocity of the particle is a constant 23.8 \( \hat{\imath} \) km/s, which is perpendicular to the magnetic field. **Problem Statement:** What, then, is the magnetic field? **Answer:** Number (\( \hat{\imath} \) + 0 \( \hat{\jmath} \) + _____ \( \hat{k} \)) Units: mT (This part of the problem hints at determining the vector components of the magnetic field. The input boxes likely correspond to vector components along \( \hat{\imath} \), \( \hat{\jmath} \), and \( \hat{k} \) directions.) (Note: There are placeholders for entering the magnetic field components; explanation of magnetic force balancing gravitational force may be needed to solve this problem.)
Transcribed Image Text:**Physics Problem: Determining the Magnetic Field** A particle of mass 11.3 g and charge 91.5 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is -9.8 \( \hat{\jmath} \) m/s\(^2\) without falling. The velocity of the particle is a constant 23.8 \( \hat{\imath} \) km/s, which is perpendicular to the magnetic field. **Problem Statement:** What, then, is the magnetic field? **Answer:** Number (\( \hat{\imath} \) + 0 \( \hat{\jmath} \) + _____ \( \hat{k} \)) Units: mT (This part of the problem hints at determining the vector components of the magnetic field. The input boxes likely correspond to vector components along \( \hat{\imath} \), \( \hat{\jmath} \), and \( \hat{k} \) directions.) (Note: There are placeholders for entering the magnetic field components; explanation of magnetic force balancing gravitational force may be needed to solve this problem.)
Expert Solution
Step 1: All the informations are write here.

Mass of the particle, m = 11.3 g

=> m = 11.3 asterisk times 10 to the power of negative 3 end exponentkg

=> m = 0.0113 kg

Charge, q = 91.5μC

=> q = 91.5 asterisk times 10 to the power of negative 6 end exponentC

=> q = 9.15 asterisk times 10 to the power of negative 5 end exponentC

The free fall acceleration is, a = - 9.8j m/s

The velocity of the particle, v = 23.8i km/s

=> v = 23.8 asterisk times 10 cubedm/s

=> v = 2.38 asterisk times 10 to the power of 4m/s

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