In the figure, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 16.5 cm Each wire carries 3.50 A, and the currents are out the page in wires 1 and 4 and into the page in wires 2 and 3. In unit-vector notation, what is the net magnetic force per meter of wire length on wire 4? Number i -2.23 î+ i 7.25 a ĴUnits N/m
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A: Ve = 7.80 x 106 mB = 1.20 x 10-5 T
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- A magnetic field has a magnitude of 0.0011 T, and an electric field has a magnitude of 5.7 x 10³ N/C. Both fields point in the same direction. A positive 1.7-µC charge moves at a speed of 2.4 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number i BA 9 V 90° UnitsA negatively charged particle experiences a force as it travels 2 900 000 m/s in a magnetic field when it is moving into the page’s direction. What is the magnitude and the direction of the magnetic field if the force is directed upward with a magnitude of 0.00000000000072 N?Two long straight current-carrying wires are lined up parallel to one another at a distance dd. Currents of 4 A and 2 A flow through the wires, both in the same direction generating the field of 3x10-6 T at a midpoint between them. Calculate the distance between the wires. Give your answer in SI units. Use μ0=4π×10−7 Hm-1.
- A long straight wire carries a current of 49.2 A. An electron, traveling at 1.00 × 107 m/s, is 8.00 cm from the wire. What force acts on the electron if the electron’s velocity is directed toward the wire? If the direction of force is perpendicular to the current, enter a negative value.Two long parallel wires carry currents of 2.91 A and 8.05 A. The magnitude of the force per unit length acting on each wire is 7.29 x 10- N/m. Find the separation distance d of the wires expressed in millimeters. d = mmA cosmic ray electron moves at 7.10 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.15 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?
- The magnetic field in the figure is decreasing at the rate 0.2 T/s. (Figure 1) You may want to review (Pages 852 - 855). Figure 2.0 cm 1 cm 1 cm 1 cm 1 of 1 ▼ Part E What is the magnitude of the acceleration of a proton at rest at point c? Express your answer to two significant figures and include the appropriate units. a= Submit Part F Value a = μA What is the direction of the acceleration of a proton at rest at point c? horizontally to the right downward Submit Request Answer Part G horizontally to the left upward a=0 19 Previous Answers Correct Here we learn how to determine the direction of the acceleration of a proton Units What is the magnitude of the acceleration of a proton at rest at point d? Express your answer to two significant figures and include the appropriate units. μÅ Value ZZZ] ? Units B rest in a s ?A proton is accelerated from rest through 2.0 kV. It then enters a uniform magnetic field of 0.30 T that is oriented perpendicular to its direction of motion. What is the radius of the path the proton follows in the magnetic field? O 11 cm O 11 mm O 22 cm O 1.1 m O 22 mm22
- A helium nucleus (2 protons, 2 neutrons) is traveling at a velocity of 5.27 x 10^6 m/s a distance of 4.88 cm away from a wire carrying a current of 3.01 A. The helium nucleus is traveling in a direction parallel to the current in the wire. How much acceleration does the helium nucleus experience due to the magnetic force from the current in the wire?A cosmic ray electron moves at 7.90 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.10 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?A proton with a mass of 4.25 x10^26 kg travels at 5.69 x10^6 m/s perpendicular to a 2.35 T magnetic field. What is the radius of the circular path of the proton? An electron with a velocity of 8.45 x10^5 m/s is perpendicular to a magnetic field with a strength of 2.15. Calculate the radius of the curvature of an electron.