A cosmic ray electron moves at 7.90 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.10 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows?

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Chapter1: Units, Trigonometry. And Vectors
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A cosmic ray electron moves at 7.90 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where field strength is 1.10 ✕ 10−5 T. What is the radius (in m) of the circular path the electron follows? 
Expert Solution
Step 1: Given data:

v equals 7.90 cross times 10 to the power of 6 space m divided by s
B equals 1.10 cross times 10 to the power of negative 5 end exponent space T
theta equals 90 degree

Need to determine the radius of rotation.

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