An automotive part must be machined to close tolerances to be acceptable to customers. Production specifications call for a maximum variance in the lengths of the parts of 0.0004. Aquality control sample produced the data in the Microsoft Excel Online file below. Using a = 0.05, test to see whether the population variance specification is being violated.XOpen spreadsheet1. Formulate the null and alternative hypotheses for this application.Ho: 0²Ha: 0²2. Test statistic =3. The p-value is4. Conclusion:5. Test results:Check My Work↑î(to 2 decimals)Reset Problemŵ↑ Excel template - SavedD3123456789File1011121314151617181920212223242526272829303132333425HomeAPart Length4.9654.9554.964.9554.9754.9854.964.9454.985.0054.9554.974.974.9854.9654.954.9754.984.9554.964.984.9855.0155.0155.0055.0155.014.9854.975BInsertArialfxDrawSheet1 +Page Layout✓ 10v BсDInferences About a Population VarianceSample sizeSample meanSample varianceSample standard deviationHypothesized varianceDegrees of freedomLevel of significanceCritical Value (2 decimals)Test statistic (2 decimals)p-value (4 decimals)Calculation Mode: Automatic Workbook StatisticsReject null hypothesis?Formulas0.00040.05↓ESearch (Option + Q)DataReviewViewVFFormulas#N/A#N/A#N/A#N/A#N/A#N/A#N/A#N/A#N/AabHelpGeneralGH←0.00.00→.0JKLMEvNEditing ✓APGive Feedback to MicrosoftPCommentsQ100% +

The data set is inserted in excel as follows:

Answered: An automotive part must be machined to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The accompanying data table contains chest deceleration measurements (in g, whereg is the force of gravity) from samples of small, midsize, and large cars. Shown are the technology results for analysis of variance of this data table. Assume that a researcher plans to use a 0.05 significance level to test the claim that the different size categories have the same mean chest deceleration in the standard crash test. Complete parts (a) and (b) below. Click the icon to view the table of chest deceleration measurements A Click the icon to view the table of analysis of variance results. ..... a. What characteristic of the data specifically indicates that one-way analysis of variance should be used? O A. There are three samples of measurements. O B. The population means are approximately normal. O C. The measurements are categorized according to the one characteristic of size. O D. Nothing specifically indicates that one-way analysis of variance should be used. b. If the objective is to test…
The variance in a production process is an important measure of the quality of the process. A large variance often signals an opportunity for improvement in the process by finding ways to reduce the process variance. Jelly Belly Candy Company is testing two machines that use different technologies to fill three pound bags of jelly beans. The following tables contain a sample of data on the weights of bags (in pounds) filled by each machine. Machine 1 Machine 2 Ho: 01 2 Ho: 01 State the null and alternative hypotheses. 2 2 Ha: 01 Ha: 01 2.95 3.45 3.50 3.75 3.48 3.26 3.33 2 Ha: 01 ≤0₂ 3.16 3.20 3.22 3.38 3.90 3.36 3.25 2 3.20 2 3.12 Ho: 01 Conduct a statistical test to determine whether there is a significant difference between the variances in the bag weights for two machines. Use a 0.05 level of significance. What is your conclusion? = 2 Ho: 01 #0 2 02 = 2 2 02 02 2 2 2 ≤02 3.20 2 2 H₂: 01 > 02 3.28 3.22 2.98 3.45 3.70 3.34 3.18 3.35 3.22 3.30 3.34 3.28 3.29 3.25 3.30 3.27 3.38 3.34…
Suppose that weights of college mathematics textbooks in the United States are normally distributed with mean µ = 2.25 lbs and variance σ2 = 0.2025 lbs. Find the weight that corresponds to Q3 and interpret this measure of position in the context of the problem.
According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, assume some state had 534 complaints of identity theft out of 1960 consumer complaints. Do these data provide enough evidence to show that that state had a higher proportion of identity theft than 23%? Test at the 6% level.P: PARAMETER What is the correct parameter symbol for this problem? What is the wording of the parameter in the context of this problem? H: HYPOTHESES Fill in the correct null and alternative hypotheses: ASSUMPTIONS Since information was collected from each object, what conditions do we need to check? Check all that apply. np≥10np≥10 n≥30n≥30 or normal population. σσ is known. σσ is unknown. N≥20nN≥20n n(1−p)≥10
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 160 engines and the mean pressure was 7.7 pounds/square inch (psi). Assume the population variance is 0.36. If the valve was designed to produce a mean pressure of 7.8 psi, is there sufficient evidence at the 0.01 level that the valve performs below the specifications? Step 3 of 3: Make the decision to reject or fail to reject the null hypothesis.
A. 2.1
3.Which model do you think is the “best” reduced model? Discuss why you choose this model. Analysis of Variance Table (Step back model) Response: rent Df Sum Sq Mean Sq F value Pr(>F) age 1 21000 21000 17.1136 0.0003079 *** sqft 1 35364 35364 28.8196 1.134e-05 *** sd 1 5961 5961 4.8576 0.0362339 * unts 1 8678 8678 7.0722 0.0130049 * gar 1 33364 33364 27.1899 1.713e-05 *** cp 1 7641 7641 6.2269 0.0189934 * Residuals 27 33131 1227 --- Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1 Step forward model: Response: rent Df Sum Sq Mean Sq F value Pr(>F) age 1 21000 21000 16.6255 0.000406 *** sqft 1 35364 35364 27.9976 1.757e-05 *** sd 1 5961 5961 4.7191 0.039517 * unts 1 8678 8678 6.8705 0.014697 * gar 1 33364 33364 26.4144 2.599e-05 *** cp 1 7641 7641 6.0493 0.021176 *…

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