Question 39. To do the above test of hypothesis, which one of the following will be the appropriate null and alternative hypothesis? (A) H₁: p0.05 vs H₁: p = 0.05 (C) Ho: p0.15 vs H₁: p = 0.15 (E) None of the above (B) H₁: p= 0.05 vs H₁: p0.05 (D) H₁: p = 0.05 vs H₁: p < 0.05

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Question 38. Based on the correct analysis, which of the following conclusions you think would be true
for the above test of hypothesis.
(A) Do not reject H₁. Data do not provide sufficient evidence to conclude that the mean number
of calls per representative per week is more than 40.
(B) Do not reject H₁. Data provide sufficient evidence to conclude that the mean number of calls
per representative per week is more than 40.
(C) Reject H₁. Data do not provide sufficient evidence to conclude that the mean number of calls
per representative per week is more than 40.
(D) Reject Ho. Data provide sufficient evidence to conclude that the mean number of calls per
representative per week is more than 40.
(E) None of the above
Questions 39-40. The reputations (and hence sales) of many businesses can be severely damaged by
shipments of manufactured items that contain a large percentage of defectives. A manufacturer of
Alkaline batteries may want to be reasonably certain that fewer than 5% of its batteries are defective.
Suppose that 300 batteries are randomly selected from a very large shipment; each is tested and 10
defective batteries are found. Manufacturer wants to know that whether this provide sufficient evidence
that the proportion of the defective in the entire shipment is less than 0.05? To do the above test, a
researcher performed two analyses using Minitab with relevant outputs below.
Analysis I Test and Cl for One Proportion
Normal approximation method is used for this analysis.
Descriptive Statistics
N Event Sample p
90% Cl for p
300 10 0.033333 (0.016286, 0.050380)
Analysis II Test and Cl for One Proportion
Normal approximation method is used for this analysis.
Descriptive Statistics
N Event Sample p
300
10 0.033333
Z-Value P-Value
-1.32 0.185
90% Upper Bound
for p Z-Value P-Value
0.046615 -1.32 0.093
Question 39. To do the above test of hypothesis, which one of the following will be the appropriate null
and alternative hypothesis?
(A) H₁: p‡ 0.05 vs H₁: p = 0.05
(C) H₁: p0.15 vs H₁: p = 0.15
(E) None of the above
(B) H₁: p= 0.05 vs H₁: p +0.05
(D) H₁: p = 0.05 vs H₁: p < 0.05
Transcribed Image Text:Question 38. Based on the correct analysis, which of the following conclusions you think would be true for the above test of hypothesis. (A) Do not reject H₁. Data do not provide sufficient evidence to conclude that the mean number of calls per representative per week is more than 40. (B) Do not reject H₁. Data provide sufficient evidence to conclude that the mean number of calls per representative per week is more than 40. (C) Reject H₁. Data do not provide sufficient evidence to conclude that the mean number of calls per representative per week is more than 40. (D) Reject Ho. Data provide sufficient evidence to conclude that the mean number of calls per representative per week is more than 40. (E) None of the above Questions 39-40. The reputations (and hence sales) of many businesses can be severely damaged by shipments of manufactured items that contain a large percentage of defectives. A manufacturer of Alkaline batteries may want to be reasonably certain that fewer than 5% of its batteries are defective. Suppose that 300 batteries are randomly selected from a very large shipment; each is tested and 10 defective batteries are found. Manufacturer wants to know that whether this provide sufficient evidence that the proportion of the defective in the entire shipment is less than 0.05? To do the above test, a researcher performed two analyses using Minitab with relevant outputs below. Analysis I Test and Cl for One Proportion Normal approximation method is used for this analysis. Descriptive Statistics N Event Sample p 90% Cl for p 300 10 0.033333 (0.016286, 0.050380) Analysis II Test and Cl for One Proportion Normal approximation method is used for this analysis. Descriptive Statistics N Event Sample p 300 10 0.033333 Z-Value P-Value -1.32 0.185 90% Upper Bound for p Z-Value P-Value 0.046615 -1.32 0.093 Question 39. To do the above test of hypothesis, which one of the following will be the appropriate null and alternative hypothesis? (A) H₁: p‡ 0.05 vs H₁: p = 0.05 (C) H₁: p0.15 vs H₁: p = 0.15 (E) None of the above (B) H₁: p= 0.05 vs H₁: p +0.05 (D) H₁: p = 0.05 vs H₁: p < 0.05
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