On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate?The data shown below ($) contains the rate per 5 CCF of residential water for 42 randomly selected U.S. cities.10.389.0811.76.412.3214.4315.4610.0214.416.0817.519.0817.8812.7516.717.2515.5414.718.8117.8914.818.3215.9526.7522.2222.6620.8823.3518.9523.619.1623.6527.726.9527.0426.8924.5837.7626.4138.9129.3641.55(a) Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa.(Enter != for # as needed.)Ho:µ = 21.62u ! = 21.2(b) What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.)-1.316What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.)0.1882 (d)Repeat the preceding hypothesis test using the critical value approach.State the null and alternative hypotheses. (Enter != for # as needed.)Ho:µ = 21.62Hạ:u! = 21.62Find the value of the test statistic. (Round your answer to three decimal places.)-1.316State the critical values for the rejection rule. Use a = 0.05. (Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)test statistic < -1.96test statistic 21.96State your conclusion.Do not reject Ho. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject Ho. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject Ho. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water inTulsa.Reject Ho. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.

Name: On its municipal website, the city of Tulsa states that the rate it c
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Description: On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate?The data shown below ($) contains the rat

(a) Let μ denotes the population mean rate per 5 CCF of residential water charged by U.S. public utilities. The test is that the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. The hypothesis is, Null hypothesis: H0:μ=21.62 Alternative hypothesis: Ha:μ!=21.62 (b) The descriptive statistics for rate is conducted using EXCEL. The software procedure is given below: Enter the data. Select Data > Data Analysis >Descriptive Statistics> OK. Enter Input Range as Rate(A1:A43) column. Mark Labels in First Row. Mark Summary Statistics. Click OK. The output using EXCEL is as follows: From the output, the mean is 20.1383, and the standard deviation is 1.2034. The test statistic is, t=x¯-μsn=20.1383-21.621.203442=-1.48171.2034=-1.231 Thus, the test statistic is -1.231. The degrees of freedom is, df=n-1=42-1=41 The degrees of freedom is 41. The hypothesis is two tailed. The probability of t not equal to 1.231 with 41 degrees of freedom can be obtained using the excel formula “=T.DIST.2T(1.231,41)”. The probability value is 0.2253. Thus, the p-value is 0.2253. Decision rule: If p-value≤α, then reject the null hypothesis. Otherwise, do not reject the null hypothesis. Conclusion: The p-value (0.2253) is greater than the level of significance (0.05). Based on decision rule, fail to reject the null hypothesis. Thus, the mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.(d) Let μ denotes the population mean rate per 5 CCF of residential water charged by U.S. public utilities. The test is that the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. The hypothesis is, Null hypothesis: H0:μ=21.62 Alternative hypothesis: Ha:μ!=21.62 The test statistic is, t=x¯-μsn=20.1383-21.621.203442=-1.48171.2034=-1.231 Thus, the test statistic is -1.231. Computation of critical value: The critical value of t-distribution for 0.05 level of significance at 41 degrees of freedom can be obtained using the excel formula “=T.INV.2T(0.05,41)”. The critical value is 2.020. Thus, the critical value is ±2.020. Thus, the critical values for the rejection rule is test statistic ≤-2.020 and test statistic ≥2.020. Conclusion: The test statistic (-1.231) is greater than the critical value (-2.020). Based on decision rule, do not reject the null hypothesis. Thus, the mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.

Math

Statistics

(a) Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. (Enter != for # as needed.) Ho: u= 21.62 H3: u! = 21.2 (b) What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.) -1.316 What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.) 0.1882

(a) Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. (Enter != for # as needed.) Ho: u= 21.62 H3: u! = 21.2 (b) What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.) -1.316 What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.) 0.1882

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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