Hi, I need help finding my P-Value and figuring out if I can reject the null hypothesis. Here is all my info that I have done to help. That is all I need help on. Thanks!   I am conducting a test of significance at level (a=.05) to determine if on average, pennies are younger than 18 years old. My hypothesis is Ho:μ=2003, Ha:μ>2003 because the current year is 2021. So 2021-18= 2003 My data is left skewed. My a=.05 My sample size is 30. x x−x̄ (x-x̄)2 1997 -18.167 330.0399 2000 -15.167 230.0379 2003 -12.167 148.0359 2005 -10.167 103.3679 2007 -8.167 66.69989 2010 -5.167 26.69789 2014 -1.167 1.361889 2015 -0.167 0.027889 2015 -0.167 0.027889 2016 0.833 0.693889 2016 0.833 0.693889 2017 1.833 3.359889 2017 1.833 3.359889 2018 2.833 8.025889 2018 2.833 8.025889 2018 2.833 8.025889 2018 2.833 8.025889 2018 2.833 8.025889 2018 2.833 8.025889 2019 3.833 14.69189 2019 3.833 14.69189 2019 3.833 14.69189 2019 3.833 14.69189 2019 3.833 14.69189 2019 3.833 14.69189 2020 4.833 23.35789 2020 4.833 23.35789 2020 4.833 23.35789 2020 4.833 23.35789 2021 5.833 34.02389 Total       60455   1178.167   My x̄ is 2015.16 work in the picture below. My s= 6.37 work in the picture below.

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Hi, I need help finding my P-Value and figuring out if I can reject the null hypothesis. Here is all my info that I have done to help. That is all I need help on. Thanks!

 

I am conducting a test of significance at level (a=.05) to determine if on average, pennies are younger than 18 years old.

My hypothesis is Ho:μ=2003, Ha:μ>2003 because the current year is 2021. So 2021-18= 2003

My data is left skewed.

My a=.05

My sample size is 30.

x x−x̄ (x-x̄)2
1997 -18.167 330.0399
2000 -15.167 230.0379
2003 -12.167 148.0359
2005 -10.167 103.3679
2007 -8.167 66.69989
2010 -5.167 26.69789
2014 -1.167 1.361889
2015 -0.167 0.027889
2015 -0.167 0.027889
2016 0.833 0.693889
2016 0.833 0.693889
2017 1.833 3.359889
2017 1.833 3.359889
2018 2.833 8.025889
2018 2.833 8.025889
2018 2.833 8.025889
2018 2.833 8.025889
2018 2.833 8.025889
2018 2.833 8.025889
2019 3.833 14.69189
2019 3.833 14.69189
2019 3.833 14.69189
2019 3.833 14.69189
2019 3.833 14.69189
2019 3.833 14.69189
2020 4.833 23.35789
2020 4.833 23.35789
2020 4.833 23.35789
2020 4.833 23.35789
2021 5.833 34.02389
Total       60455   1178.167

 

My x̄ is 2015.16 work in the picture below.

My s= 6.37 work in the picture below.

 

My t-procedure is =0.34 work in the picture below. 

My mean and standerd deuiation is:
X= 2015.16
S= 6037
Nouw I can calculate the t-procedure
+%3X-H0-D2015.16-2003-0.34
S/n
%3D
l6037530
The degrees of freedom for the testis
n-1=30-1=29
Transcribed Image Text:My mean and standerd deuiation is: X= 2015.16 S= 6037 Nouw I can calculate the t-procedure +%3X-H0-D2015.16-2003-0.34 S/n %3D l6037530 The degrees of freedom for the testis n-1=30-1=29
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