An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of VA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in terms of mA, mg and VA: Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf =0 Substituting the expression for momentum results to mgV mAV = 0 Deriving the expression for the velocity of piece B results to V =(mA/m VA

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Chapter1: Units, Trigonometry. And Vectors
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An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed
of VA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in terms of ma, mg and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf + PAf = 0
Substituting the expression for momentum results to
mgv
mAV
= 0
Deriving the expression for the velocity of piece B results to
V
=(ma/m
VA
Transcribed Image Text:An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of VA. Piece B with mass mg travels to the right with speed vg. Show the velocity of piece B in terms of ma, mg and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf = 0 Substituting the expression for momentum results to mgv mAV = 0 Deriving the expression for the velocity of piece B results to V =(ma/m VA
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