Consider a thin square plate on the z = 0 plane with mass density given by o(x, y) = C ((x - 1)²y² + x¹y²), and whose total mass is M. The plate has a side length of two meters, and its center lies at the origin. The infinitesimal mass element is given by: dM = 0 o(x, y) dxdy
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- An object is made of glass and has the shape of a cube 0.12 m on a side, according to an observer at rest relative to it. However, an observer moving at high speed parallel to one of the object's edges and knowing that the object's mass is 3.4 kg determines its density to be 8700 kg/m³, which is much greater than the density of glass. What is the moving observer's speed (in units of c) relative to the cube? Rest frame of cube KL-Lo Rest frame of observerIf one mass is much greater than the other, the larger mass stays essentially at rest while the smaller mass moves toward it. Suppose a 1.5×1013 kg comet is passing the orbit of Mars, heading straight for the 1.99×1030 kg sun at a speed of 4.5 ×104 m/s. What will its speed be when it crosses the orbit of Mercury? The orbit of Mars is 2.28×108 km, the orbit of Mercury is 5.79×107 km, and G = 6.67×10-11 N⋅m2/kg2.An unstable particle at rest breaks up into two fragments of unequal mass. The mass of the lighter fragment is equal to 2.60 x 10° -28 kg and that of the heavier fragment is 1.66 × 10° -27 kg. If the lighter fragment has a speed of 0.893c after the breakup, what is the speed of the heavier fragment?
- 15 mc 4 mc The static energy Eo of a particle of mass m is one fourth of its total energy E. What is the particle's momentum in mc units? √3 mc 715 mc 3 mcAn unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is m1 = 2.50 x 10-28 kg, and that of the other is m2 = 1.67 x 10-27 kg. If the speed of m1 is equal to 0.893c after the breakup, where c = 3 x 108 m/s. What is the final speed of m2?In special relativity, we introduced the momentum of a particle in a given Lorentz frame as pu = (E, pi ), where E is the energy of the particle and pi is the relativistic 3-momentum. Explain why, in general relativity, the energy of a particle measured by an observer is given, irrespective of the coordinate system used, by −p · uobs, where pu is the momentum of the particle and uuobs is the velocity of the observer in those coordinates.
- The kinetic energy of a mass moving in the x-y plane is: T = mx² + my² Using the transformation = rcos (0) and y = rsin (0), derive a general expression for kinetic energy of the mass in the r, basis.James (mass 81.0 kg) and Ramon (mass 57.0 kg) are 20.0 m apart on a frozen pond. Midway between them is a mug of their favorite beverage. They pull on the ends of a light rope stretched between them. Ramon pulls on the rope to give himself a speed of 1.10 m/s. What is James's speed? It must have the proper dimensions of speed.C Chegg X C Sign In https://bconline.broward.edu/d21/lms/quizzing/user/attempt/quiz_start_frame_auto.d2l?ou=514283&is... A Q If a projectile mass of 1.0 kg moving at 19.0 m/s collides with a motionless target mass of 15.0 kg perfectly inelastically what is the total kinetic energy of the projectile and target after the collision? X 1 OneLoc X Quizzes X Q instagra X Your Answer: Use standard MKS unit abbreviations. Instagra X Answer units (75,834 X C Reset P. X X New ta X + {}
- The muon is an unstable subatomic particle witha mean lifetime of 2.2 μs, and about 10,000 muons reach everysquare meter of the earth's surface a minute. A muon has a linear momentum G, and after some short time it decays into two other elementary particles with masses m1 and m2. The energy Q released during the decay is converted entirely into the kinetic energy of the decay products (i.e., into kinetic energy of m1 and m2). Find linear momenta of decay products. Draw a vector diagram showing a range of momenta decay products can take.An unstable particle is at rest and suddenly breaks up into two fragments. No external forces act on the particle or its fragments. One of the fragments has a velocity of +0.837c and a mass of 1.77 × 10-27 kg, and the other has a mass of 5.29 × 10-27 kg. What is the velocity of the more massive fragment (as a multiple of c)? (Hint: This problem is similar to Example 6 in Chapter 7.) Unstable particle at rest Number i V2 m2 Units m1 V1 Recoiling fragmentsTwo manned satellites approaching one another, at a relative speed of 0.200 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. a. Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) m/s b. What is the loss of kinetic energy (in J) in this inelastic collision? J c. Repeat both parts by using the frame of reference in which the second satellite was originally at rest. final velocity (m/s) m/sloss of kinetic energy (J) J Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both.