In special relativity, we introduced the momentum of a particle in a given Lorentz frame as pu = (E, pi ), where E is the energy of the particle and pi is the relativistic 3-momentum. Explain why, in general relativity, the energy of a particle measured by an observer is given, irrespective of the coordinate system used, by −p · uobs, where pu is the momentum of the particle and uuobs is the velocity of the observer in those coordinates.
In special relativity, we introduced the momentum of a particle in a given Lorentz frame as pu = (E, pi ), where E is the energy of the particle and pi is the relativistic 3-momentum. Explain why, in general relativity, the energy of a particle measured by an observer is given, irrespective of the coordinate system used, by −p · uobs, where pu is the momentum of the particle and uuobs is the velocity of the observer in those coordinates.
Related questions
Question
In

Transcribed Image Text:In special relativity, we introduced the momentum of a particle in a given Lorentz frame as p¹ =
(E,p²), where E is the energy of the particle and p¹ is the relativistic 3-momentum. Explain why,
in general relativity, the energy of a particle measured by an observer is given, irrespective of the
coordinate system used, by -p Uobs, where p¹ is the momentum of the particle and us is the
velocity of the observer in those coordinates.
obs
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 1 images
