A rod is made of two different layers: chromium and copper; as shown in the diagram below. Both layers have the same length ( L=0.46 m) and the same area (A = 0.13 cm2). In the considered system, chromium is joined to the left hand which is at Tief =74.8 C, whereas copper is in physical contact with the right end at Tght =7 C. The thermal conductivity constants of the materials are given as k, = 93.7 W/(m K) and k, =401 W/(m K). Assuming steady state is eventually achieved, answer %3D the following questions. a) Evaluate the junction temperature between the two layers. Tjunction %3D b) Calculate the rate of heat flow (power) through conduction in Sl units. P= J/s Teft Layer 1 Layer 2 Tright

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Chapter1: Units, Trigonometry. And Vectors
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A rod is made of two different layers: chromium and copper; as shown in the diagram below. Both layers have the same length (
L0.46 m) and the same area (A = 0.13 cm²). In the considered system, chromium is joined to the left hand which is at
Tien =74.8 C, whereas copper is in physical contact with the right end at T,
the materials are given as k, = 93.7 W/(m K) and k,= 401 W/(m K). Assuming steady state is eventually achieved, answer
=7 C. The thermal conductivity constants of
right
the following questions.
a) Evaluate the junction temperature between the two layers. Tjunction
b) Calculate the rate of heat flow (power) through conduction in SI units. P=
J/s
Tieft
Layer 1
Layer 2
Tright
Check
Next page
Jump to...
64
Transcribed Image Text:A rod is made of two different layers: chromium and copper; as shown in the diagram below. Both layers have the same length ( L0.46 m) and the same area (A = 0.13 cm²). In the considered system, chromium is joined to the left hand which is at Tien =74.8 C, whereas copper is in physical contact with the right end at T, the materials are given as k, = 93.7 W/(m K) and k,= 401 W/(m K). Assuming steady state is eventually achieved, answer =7 C. The thermal conductivity constants of right the following questions. a) Evaluate the junction temperature between the two layers. Tjunction b) Calculate the rate of heat flow (power) through conduction in SI units. P= J/s Tieft Layer 1 Layer 2 Tright Check Next page Jump to... 64
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