An atom of uranium-235 (atomic 235.04392 u) de- 39.8 mass: m(23U) cays to thorium-231 (atomic mass: m(231 Th) = 231.03630 u) n 92 via the 90 a particle (nuclear 4.00151 u). emission of an mass: m(a) c = 2.998 x 108 m s-1. Use (a) What is the binding energy of an 235U nucleus (in J)? 92 (b) What is the binding energy of a 231 Th nucleus (in J)? 90 (c) What is the binding energy of an a particle (in J)?
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- B3. In the alpha decay of uranium 232U → 228Th + He, how much kinetic energy (in MeV) will 90 the thorium atom have. Given that Q = 6.46 MeV and the atomic mass of 220Th is 228.028731u. Express the values to 3 significant figures, if necessary.Answers to d and e pleaseConsider the following decay: 232 U 92 a mass of 4.002603 u. 228 Th+ a. 232 U has a mass of 232.0371562 u, 228 Th has a mass of 228.0287411 u, and a has 90 92 90 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE= KE=Qx D.) Determine the speed of the particle in terms of c. For an a particle, E = 3.727 GeV. [NOTE: G stands for giga- which means 10º & M stands for mega- which means 106.] Vα = XC
- Consider the following a-decay of the Uranium nucleus 236 U → 332Th + a. 90 (a) Show how the mass number (Aa) and atomic number (Za) of the alpha particle are obtained from this equation. (b) Calculate the Q-value (Qa) of the reaction. (c) Calculate the speed va = √2MQ of the alpha particle after it has been ejected from the parent nucleus, in terms of the speed of light c. M = -, mp and ma are the atomic masses (ma+mp) x ma mp of the daugher nucleus and the alpha particle, respectively. (d) Calculate the classical turning radius Re= 2Zpe²/Qa, where Zp is the atomic number of the daughter nucleus, and e² = 1.44 MeV. fm. (e) Calculate the decay probability Pa that the alpha particle will tunnel through the barrier. HINT: In calculating the probability, use the fact that ħc=197.327 MeV fm. The formula to use is given on page 5.Consider the following decay: 209 83 Bi->> 205 TI + α. 81 209 Bi has a mass of 208.9803987 u, 205 TI has a mass of 204.9744275 u, and a has a mass of 4.002603 u. 81 83 A.) Determine the disintegration energy (Q-value) in MeV. Q= B.) Determine the KE of the daughter in MeV. KED= C.) Determine the KE of the a particle in MeV & as a factor of Q. KE = KE=Qx D.) Determine the speed of the a particle in terms of c. For an a particle, E, = 3.727 GeV. [NOTE: G stands for giga- which means 109 &M stands for mega- which means 106.] XCThe nucleus of a lithium atom is 3 ^ 7 Li and its mass is 7.0160 amu. Calculate the binding energy in MeV. The relevant masses are, for the neutron, 1.0087 amu, and the proton 1.0073 amu. 1 amu is equivalent to 931 MeV
- On absorption of a single neutron, plutonium Pu-239 can undergo fission into xenon Xe-134 plus zirconium Zr-103 plus three neutrons. The masses of these nuclei are, mpu-239 = 239.052 amu, mxe-134 = 133.905 amu, and mzr-103 = 102.927 amu. Calculate the energy given off in this nuclear reaction.In nuclear reaction: [ 220Rn ? 216Po + α ] a Radon-220 atom undergoes alpha decay. The components have these atomic mass energies: 220Rn : 204941 MeV, 216Po : 201206 MeV, α : 3727 MeV. About how much energy is released in this reaction?A thorium-228 atom (mass = 228.0287 u) decays to radium-224 (mass = 224.0202 u) through alpha emission (mass 4.0026 u). The equation is shown below. How much energy is released from this reaction? 228Th - 90 224 Ra +He+energy (a) 1.2 MeV (b) 2.4 MeV (c) 4.1 MeV (d) 5.5 MeV