A thorium-228 atom (mass 228.02 u) décays to radium-224 (mass 224.0202 u) through alpha emission (mass = 4.0026 u). The equation is shown below. How much energy is released from this reaction? Th → Ra +¿He+ energy 90 88 (a) 1.2 MeV (b) 2.4 MeV (c) 4.1 MeV (d) 5.5 MeV
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- 6. Given the information below, how much energy is emitted in the reaction? 22.9945 mass ofNe 23 1Ne Na +e + v 1 mass of Na 22.9898 u 11 mass of Çe 0.00055 u (A) 3.87 MeV (B) 4.15 MeV (C) 4.38 MeV (D) 4.89 MeVB3. In the alpha decay of uranium 232U → 228Th + He, how much kinetic energy (in MeV) will 90 the thorium atom have. Given that Q = 6.46 MeV and the atomic mass of 220Th is 228.028731u. Express the values to 3 significant figures, if necessary.Answers to d and e please
- A nuclei has a mass of 6.51×10-27 kg. What is its mass in Mev/c²? 3.65x10³ Mev/c² 3.92 Mev/² 7.85x10³ Mev/c² Question 3 Is the following decay possible? 232Th (Z=90) 236µ (Z = 92) + a 000 It's impossible to tell No YesConsider the following a-decay of the Uranium nucleus 236 U → 332Th + a. 90 (a) Show how the mass number (Aa) and atomic number (Za) of the alpha particle are obtained from this equation. (b) Calculate the Q-value (Qa) of the reaction. (c) Calculate the speed va = √2MQ of the alpha particle after it has been ejected from the parent nucleus, in terms of the speed of light c. M = -, mp and ma are the atomic masses (ma+mp) x ma mp of the daugher nucleus and the alpha particle, respectively. (d) Calculate the classical turning radius Re= 2Zpe²/Qa, where Zp is the atomic number of the daughter nucleus, and e² = 1.44 MeV. fm. (e) Calculate the decay probability Pa that the alpha particle will tunnel through the barrier. HINT: In calculating the probability, use the fact that ħc=197.327 MeV fm. The formula to use is given on page 5.An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of 14C. Find the minimum age (in years) of the charcoal. Carbon-14 has a half-life of 5730 years which means half of it will be gone after 5730 years. You may find the equality 210 = 1024 to be useful.