A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioactive 32P isotope with a half-life of 14.3 days and which decays via beta emission with an energy of 1.71MeV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 10 J of energy into it. The other half of the solution is dispersed throughout the patients’ tissues, also depositing 9 J of energy into the 50.0 kg of body tissues. (a) What is the dose (in Gy and rem) that the tumor receives? (b) What is the dose (in Gy and rem) that the rest of the patient receives?
A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the radioactive 32P isotope with a half-life of 14.3 days and which decays via beta emission with an energy of 1.71MeV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 10 J of energy into it. The other half of the solution is dispersed throughout the patients’ tissues, also depositing 9 J of energy into the 50.0 kg of body tissues. (a) What is the dose (in Gy and rem) that the tumor receives? (b) What is the dose (in Gy and rem) that the rest of the patient receives?
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3. A 14 g ovarian tumor is treated using a sodium phosphate solution in which the phosphorus atoms are the
radioactive 32P isotope with a half-life of 14.3 days and which decays via beta emission with an energy of 1.71MeV. Half of the sodium phosphate solution is absorbed by the tumor and deposits 10 J of energy into it.
The other half of the solution is dispersed throughout the patients’ tissues, also depositing 9 J of energy into the
50.0 kg of body tissues. (a) What is the dose (in Gy and rem) that the tumor receives? (b) What is the dose (in Gy
and rem) that the rest of the patient receives?
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