/* * allEvenBits - return 1 if all even-numbered bits in word set to 1 * Examples allEvenBits(0xFFFFFFFE) = 0, allEvenBits(0x55555555) = 1 * Legal ops: ! ~ & ^ | + << >> * Max ops: 12 * Rating: 2 */ int allEvenBits(int b) { return 2; }
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/*
* allEvenBits - return 1 if all even-numbered bits in word set to 1
* Examples allEvenBits(0xFFFFFFFE) = 0, allEvenBits(0x55555555) = 1
* Legal ops: ! ~ & ^ | + << >>
* Max ops: 12
* Rating: 2
*/
int allEvenBits(int b) {
return 2;
}
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- C++ LANGUAGE Write a program that asks for two integers X and Y as input and creates two arrays with sizes X and Y using calloc. Then, ask for the elements of the two arrays using a loop of your preference and concatenate the two arrays into one. Elements in X must come first. One line containing an integer for the size of the array X Print the concatenated elements inside a pair of square brackets [ ] where each elements are separated by a comma and a space. At the end of the program, don't forget to free the memory space. Input 1. One line containing an integer for the size of the array X 2. One or more lines containing an integer for the elements of array X 3. One line containing an integer for the size of the array Y 4. One or more lines containing an integer for the elements of array Y OUTPUT: Enter size of array 1: 3 Enter element 1: 1 Enter element 2: 2 Enter element 3: 3 Enter size of array 2: 2 Enter element 1: 4 Enter element 2: 5 [1, 2, 3, 4, 5]#include<stdio.h>#include<string.h>struct info{char names[100];int age;float wage;};int main(int argc, char* argv[]) {int line_count = 0;int index, i;struct info hr[10];if (argc != 2)printf("Invalid user_input!\n");else {FILE* contents = fopen (argv[1], "r");struct info in;if (contents != NULL) {printf("File has been opened successfully.\n\n");while (fscanf(contents, "%s %d %f\n",hr[line_count].names, &hr[line_count].age, &hr[line_count].wage) != EOF) {printf("%s %d %f\n", hr[line_count].names, hr[line_count].age, hr[line_count].wage);line_count++;}printf("\nTotal number of lines in document are: %d\n\n", line_count);fclose(contents);printf("Please enter a name: ");char user_input[100];fgets(user_input, 30, stdin);user_input[strlen(user_input)-1] = '\0';index = -1;for(i = 0; i < line_count; i++){if(strcmp(hr[i].names, user_input) == 0){index = i;break;}}if(index == -1)printf("Name %s not found\n", user_input);else{while(fread(&in, sizeof(struct info), 1,…Caesars Cypher in C programming language How do you program an encryption and decryption for a Caesars Cypher that covers all the possible ASCII characters? In this there should be a shift over K = 5 but the example below is K = 3. This should result in actual character and not the control ASCII represenations. For example: >>> $ encrypt(I have a key)N%mf{j%f%pj~>>> $ encrypt(see me at 3)xjj%rj%fy%8>>> $ decrpyt(|jfw%ns%gqzj)wear in blue Assume that the text parsing method has been succesful and it's the encryption/decryption of the char array that needs to be factored. Formula Encryption -> C = E(k, P) = (P + k) (mod 26) Decryption -> P = D(k, C) = (C - k) (mod 26) Where k = 5
- #include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…lst = [10, 20, 30, 40, 50, 60, 70, 80] def f(lst, seek): for i in range(len(lst)): if lst[i] == seek: return i # Return position immediately return None f(lst,50) What is the output of this code part? A)3 B)4 C)5 D)none#include <stdio.h> #include <string.h> int IsPasswordOkay(char* pass) { char Password[12]; strcpy(Password, pass); if (!strcmp(Password, "goodpass")) return(1); else return(0); } int main(int argc, char **argv) { int PwStatus; if (argc < 2) { printf("Input your password\n"); return(-1); } PwStatus = IsPasswordOkay(argv[1]); if (PwStatus == 0) { printf("Acces denied"); return(-1); } else { printf("Access granted"); return(1); } } Write a function to conduct input validation to secure the smallest buffer. You may call this function void SecurePasswordBuffer(const char *arg).
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