eturns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val

eturns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val

Np Ms Office 365/Excel 2016 I Ntermed

1st Edition

ISBN:9781337508841

Author:Carey

Publisher:Carey

Chapter3: Performing Calculations With Formulas And Functions

Section: Chapter Questions

Problem 3.10CP

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Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…
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