To receive full marks on this function, your solution must not remove any keys from the parameter totals, even temporarily, such as by using the method dict.clear() 11 11 11 def update_amounts (totals: dict[str, int], amts: list[tuple[str, int]])-> None: """Update the relevant values in the totals dictionary by the new amounts from each tuple given in amts. The first element in each tuple in amts represents the key in the totals dictionary whose value must be updated by the second element in that tuple. If no such key exists, a new key-value pair with the tuple's elements are added to the totals dictionary. >>> D = >>> update_amounts(D, [('visa', 1000), ('amex', 50), ('visa', 500)]) >>> D {'visa': 1500, 'amex': 50} >>> update_amounts(D, [('amex', 50), ('visa', 1000), ('mc', 100)]) >>> D {'visa': 2500, 'amex': 100, 'mc': 100} >>> update_amounts(D, [('paypal', 25), ('amex', -100)]) >>> D {'visa': 2500, 'amex': 0, 'mc': 100, 'paypal': 25} 11 11 11

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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# TODO complete the body of this function
if __name_____
import doctest
#doctest.testmod()
__main__':
==
Transcribed Image Text:# TODO complete the body of this function if __name_____ import doctest #doctest.testmod() __main__': ==
# Fall 2018 Q8
""Complete the function below to according to its docstring.
To receive full marks on this function, your solution must not remove any keys
from the parameter totals, even temporarily, such as by using the method
dict.clear()
11 11 11
def update_amounts (totals: dict[str, int], amts: list[tuple[str, int]]) -> None:
"""Update the relevant values in the totals dictionary by the new amounts
from each tuple given in amts.
The first element in each tuple in amts represents the key in the
totals dictionary whose value must be updated by the second element
in that tuple.
If no such key exists, a new key-value pair with the tuple's elements
are added to the totals dictionary.
>>> D = {}
>>> update_amounts(D, [('visa', 1000), ('amex', 50), ('visa', 500)])
>>> D
{'visa': 1500, 'amex': 50}
>>> update_amounts(D, [('amex', 50), ('visa', 1000), ('mc', 100)])
>>> D
{'visa': 2500, 'amex': 100, 'mc': 100}
>>> update_amounts(D, [('paypal', 25), ('amex', -100)])
>>> D
{'visa': 2500, 'amex': 0, 'mc': 100, 'paypal': 25}
"11
1
Transcribed Image Text:# Fall 2018 Q8 ""Complete the function below to according to its docstring. To receive full marks on this function, your solution must not remove any keys from the parameter totals, even temporarily, such as by using the method dict.clear() 11 11 11 def update_amounts (totals: dict[str, int], amts: list[tuple[str, int]]) -> None: """Update the relevant values in the totals dictionary by the new amounts from each tuple given in amts. The first element in each tuple in amts represents the key in the totals dictionary whose value must be updated by the second element in that tuple. If no such key exists, a new key-value pair with the tuple's elements are added to the totals dictionary. >>> D = {} >>> update_amounts(D, [('visa', 1000), ('amex', 50), ('visa', 500)]) >>> D {'visa': 1500, 'amex': 50} >>> update_amounts(D, [('amex', 50), ('visa', 1000), ('mc', 100)]) >>> D {'visa': 2500, 'amex': 100, 'mc': 100} >>> update_amounts(D, [('paypal', 25), ('amex', -100)]) >>> D {'visa': 2500, 'amex': 0, 'mc': 100, 'paypal': 25} "11 1
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