Alfred was tasked to synthesize at least 250.0 ppm of his novel gold nanoparticles (AuNP’s) to be able to perform experiments about the efficacy of AuNP for viral detection. He decided to check whether he still needed to synthesize more or not using a UV Vis spectrophotometer. Fortunately, he already prepared a 100.0 ppm AuNP standard solution beforehand. He got a different aliquot of the standard, added stabilizing solutions, and diluted them to 10.0 mL for the determination of absorbance. Data he obtained is shown below. Table 1. Calibration curve data for AuNP v of 100.0 ppm AuNP standard, mL Absorbance 0.00 0.200 0.50 0.450 1.00 0.510 1.50 0.600 2.00 0.680 3.00 0.810 4.00 0.950 After obtaining the calibration curve, he got a 3.00-mL aliquot of the pre-prepared solution, added stabilizing solution, and diluted it to 10 mL. He got 10mL of the final solution and determined its absorbance to be 0.650. The absorbance of the blank solution for the sample solution was 0.200. a. Fill up the table and determine the calibration curve (Abs vs ppm) with r2 value. Express the equation of the line and r2 in 3 significant figures v of 100.0 ppm AuNP standard, mL [AuNP], ppm True Absorbance 0.00 Answer Answer 0.50 Answer Answer 1.00 Answer Answer 1.50 Answer Answer 2.00 Answer Answer 3.00 Answer Answer 4.00 Answer Answer y = ___ x + ____ r2 = __
Alfred was tasked to synthesize at least 250.0 ppm of his novel gold nanoparticles (AuNP’s) to be able to perform experiments about the efficacy of AuNP for viral detection. He decided to check whether he still needed to synthesize more or not using a UV Vis spectrophotometer.
Fortunately, he already prepared a 100.0 ppm AuNP standard solution beforehand. He got a different aliquot of the standard, added stabilizing solutions, and diluted them to 10.0 mL for the determination of absorbance. Data he obtained is shown below.
Table 1. Calibration curve data for AuNP
v of 100.0 ppm AuNP standard, mL |
Absorbance |
0.00 |
0.200 |
0.50 |
0.450 |
1.00 |
0.510 |
1.50 |
0.600 |
2.00 |
0.680 |
3.00 |
0.810 |
4.00 |
0.950 |
After obtaining the calibration curve, he got a 3.00-mL aliquot of the pre-prepared solution, added stabilizing solution, and diluted it to 10 mL. He got 10mL of the final solution and determined its absorbance to be 0.650. The absorbance of the blank solution for the sample solution was 0.200.
v of 100.0 ppm AuNP standard, mL |
[AuNP], ppm |
True Absorbance |
0.00 |
Answer | Answer |
0.50 |
Answer | Answer |
1.00 |
Answer | Answer |
1.50 |
Answer | Answer |
2.00 |
Answer | Answer |
3.00 |
Answer | Answer |
4.00 |
Answer | Answer |
y = ___ x + ____ r2 = __
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