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entration of solution 1 is 0.001 M. The consequent solutions were prepared by two-fold serial dilution. ion number ion 1 ion 2 ion 3 ion 4 ion 5 ion 6 ion 7 ion 8 ion 9 ion 10 Absorbance (342 nm) of octanol solution, initial 4 (overloaded) 4 (overloaded) 3.36 (too high) 1.658 0.831 0.482 0.268 0.173 0.086 (too low) 0.042 (too low) Absorbance(342 nm) of octanol solution, after shaking with water 1.650 0.810 0.452 0.253 0.154

entration of solution 1 is 0.001 M. The consequent solutions were prepared by two-fold serial dilution. ion number ion 1 ion 2 ion 3 ion 4 ion 5 ion 6 ion 7 ion 8 ion 9 ion 10 Absorbance (342 nm) of octanol solution, initial 4 (overloaded) 4 (overloaded) 3.36 (too high) 1.658 0.831 0.482 0.268 0.173 0.086 (too low) 0.042 (too low) Absorbance(342 nm) of octanol solution, after shaking with water 1.650 0.810 0.452 0.253 0.154

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Data for finding log P of p-toluoyl penicillin Concentration of solution 1 is 0.001 M. The consequent solutions were prepared by two-fold serial dilution. Solution number Solution 1 Solution 2 Solution 3 Solution 4 Solution 5 Solution 6 Solution 7 Solution 8 Solution 9 Solution 10 Absorbance (342 nm) of octanol solution, initial 4 (overloaded) 4 (overloaded) 3.36 (too high) 1.658 0.831 0.482 0.268 0.173 0.086 (too low) 0.042 (too low) Absorbance(342 nm) of octanol solution, after shaking with water 1.650 0.810 0.452 0.253 0.154 Determination of logP from your data: Plot a calibration graph using initial absorbance data. Use this calibration graph to find concentrations of penicillin in octanol solutions after shaking them with water. The difference between initial and new penicillin concentrations in octanol solutions will give you amount of penicillin that moved into the aqueous phase in each case. Finally, calculate the log P for each solution using the following formula: logP = log- C(octanol) C(aqueous) where C(octanol) is concentration of penicillin in octanol after shaking it with water, and C(aqueous) is concentration of penicillin in water. Once you have several values for log P, choose 3-4 closest values and average them to find a final value of log P. Compare it to the one found
Transcribed Image Text:Data for finding log P of p-toluoyl penicillin Concentration of solution 1 is 0.001 M. The consequent solutions were prepared by two-fold serial dilution. Solution number Solution 1 Solution 2 Solution 3 Solution 4 Solution 5 Solution 6 Solution 7 Solution 8 Solution 9 Solution 10 Absorbance (342 nm) of octanol solution, initial 4 (overloaded) 4 (overloaded) 3.36 (too high) 1.658 0.831 0.482 0.268 0.173 0.086 (too low) 0.042 (too low) Absorbance(342 nm) of octanol solution, after shaking with water 1.650 0.810 0.452 0.253 0.154 Determination of logP from your data: Plot a calibration graph using initial absorbance data. Use this calibration graph to find concentrations of penicillin in octanol solutions after shaking them with water. The difference between initial and new penicillin concentrations in octanol solutions will give you amount of penicillin that moved into the aqueous phase in each case. Finally, calculate the log P for each solution using the following formula: logP = log- C(octanol) C(aqueous) where C(octanol) is concentration of penicillin in octanol after shaking it with water, and C(aqueous) is concentration of penicillin in water. Once you have several values for log P, choose 3-4 closest values and average them to find a final value of log P. Compare it to the one found
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