A solvent passes through a chromatography column in 3.87 min, but the solute requires 7.60 min. What is the retention factor, k? k = What fraction of the time does the solute spend in the mobile phase in the column? tfraction in mobile phase = The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (Vs = 0.133V). What is the distribution constant, Kp, for this system? Kp =
A solvent passes through a chromatography column in 3.87 min, but the solute requires 7.60 min. What is the retention factor, k? k = What fraction of the time does the solute spend in the mobile phase in the column? tfraction in mobile phase = The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (Vs = 0.133V). What is the distribution constant, Kp, for this system? Kp =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Chromatography Analysis: Understanding Retention Factor, Mobile Phase Fraction, and Distribution Constant**
In this exercise, you will learn to calculate key parameters used in chromatography analysis: the retention factor, time fraction in the mobile phase, and distribution constant. These are essential for understanding the interactions within a chromatography column.
### Problem Statement
A solvent passes through a chromatography column in 3.87 minutes, but the solute requires 7.60 minutes.
#### 1. What is the retention factor, \( k \)?
\[
k = \text{(retention time of solute)} - \text{(retention time of solvent)}
\]
Enter your calculated value for \( k \) here: \_\_\_\_\_\_\_\_\_\_
#### 2. What fraction of the time does the solute spend in the mobile phase in the column?
\[
t_{\text{fraction in mobile phase}} = \frac{\text{retention time of solvent}}{\text{retention time of solute}}
\]
Enter the time fraction here: \_\_\_\_\_\_\_\_\_\_
#### 3. The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (\( V_S = 0.133V_M \)). What is the distribution constant, \( K_D \), for this system?
\[
K_D = \frac{k}{V_S/V_M}
\]
Enter the distribution constant here: \_\_\_\_\_\_\_\_\_\_
By determining these values, you will gain valuable insight into the dynamics and efficiency of separation within the chromatography system.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F83ec917b-3e82-4dc1-b5e7-24fa4bff0896%2F43f29aa6-4ab4-44ff-b1d5-fc5d7b47861f%2Fglj1cfk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Chromatography Analysis: Understanding Retention Factor, Mobile Phase Fraction, and Distribution Constant**
In this exercise, you will learn to calculate key parameters used in chromatography analysis: the retention factor, time fraction in the mobile phase, and distribution constant. These are essential for understanding the interactions within a chromatography column.
### Problem Statement
A solvent passes through a chromatography column in 3.87 minutes, but the solute requires 7.60 minutes.
#### 1. What is the retention factor, \( k \)?
\[
k = \text{(retention time of solute)} - \text{(retention time of solvent)}
\]
Enter your calculated value for \( k \) here: \_\_\_\_\_\_\_\_\_\_
#### 2. What fraction of the time does the solute spend in the mobile phase in the column?
\[
t_{\text{fraction in mobile phase}} = \frac{\text{retention time of solvent}}{\text{retention time of solute}}
\]
Enter the time fraction here: \_\_\_\_\_\_\_\_\_\_
#### 3. The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (\( V_S = 0.133V_M \)). What is the distribution constant, \( K_D \), for this system?
\[
K_D = \frac{k}{V_S/V_M}
\]
Enter the distribution constant here: \_\_\_\_\_\_\_\_\_\_
By determining these values, you will gain valuable insight into the dynamics and efficiency of separation within the chromatography system.
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