**Chromatography Analysis: Understanding Retention Factor, Mobile Phase Fraction, and Distribution Constant**In this exercise, you will learn to calculate key parameters used in chromatography analysis: the retention factor, time fraction in the mobile phase, and distribution constant. These are essential for understanding the interactions within a chromatography column.### Problem StatementA solvent passes through a chromatography column in 3.87 minutes, but the solute requires 7.60 minutes.#### 1. What is the retention factor, \( k \)?\[ k = \text{(retention time of solute)} - \text{(retention time of solvent)}\]Enter your calculated value for \( k \) here: \_\_\_\_\_\_\_\_\_\_#### 2. What fraction of the time does the solute spend in the mobile phase in the column?\[ t_{\text{fraction in mobile phase}} = \frac{\text{retention time of solvent}}{\text{retention time of solute}}\]Enter the time fraction here: \_\_\_\_\_\_\_\_\_\_#### 3. The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (\( V_S = 0.133V_M \)). What is the distribution constant, \( K_D \), for this system?\[ K_D = \frac{k}{V_S/V_M}\]Enter the distribution constant here: \_\_\_\_\_\_\_\_\_\_By determining these values, you will gain valuable insight into the dynamics and efficiency of separation within the chromatography system.

Answer :- 1) Retention factor (k) = 0.964 2) tfraction in mobile phase = 0.51 3) Distribution…

A solvent passes through a chromatography column in 3.87 min, but the solute requires 7.60 min. What is the retention factor, k? k = What fraction of the time does the solute spend in the mobile phase in the column? tfraction in mobile phase = The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (Vs = 0.133V). What is the distribution constant, Kp, for this system? Kp =

A solvent passes through a chromatography column in 3.87 min, but the solute requires 7.60 min. What is the retention factor, k? k = What fraction of the time does the solute spend in the mobile phase in the column? tfraction in mobile phase = The volume of the stationary phase is 0.133 times the volume of the mobile phase in the column (Vs = 0.133V). What is the distribution constant, Kp, for this system? Kp =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Consider Table 1, which lists the volumes of the Fe3+ and SCN- solutions used for the continuous variation method. Note that each of the stock solutions is 0.002 M before mixing. What are the initial concentrations of Fe3+ and SCN- for solution 4, where the volumes are both 5 mL? [Initial meaning after they are mixed, but before]they reach equilibrium)
What mass of MgCl₂ 6H₂O is required to make a 0.200 dm³ stock solution containing 25.0 ppm Mg(II)? What volumes of this stock solution are required to make 10.0 cm³ standard solutions containing 5.00, 1.00 and 0.10 ppm Mg(II)?
4- A sample containing H2C204 had a purity equal to 90.50% (w/w). An unknown mass of this sample was dissolved in water and transferred to a 50.00 mL flask. An aliquot of 25.00 mL was transferred to an erlenmeyer flask and 50.00 mL of a 0.2000 mol L^-1 NaOH solution were added. %3 Excess NaOH was titrated with 0.09000 mol L^-1 HCI solution using 2.000 mL. Calculate the mass (g) of the sample used. Data: H = 1.008 C= 12.01 O = 16.00
6
A 100 ml bottle of metronidazole 100 mg/ml suspension is available in your pharmacy. Calculate the volume of this suspension needed to be diluted with cherry syrup to prepare 60 ml of a 4% metronidazole suspension. 1 ml of a 1:1000 epinephrine injection was mixed with 20 ml of 1% lidocaine injection. Calculate the new ratio strength of epinephrine in the admixture. (IGNORE ANY VOLUME CHANGES AFTER ADMIXTURE) Instead of preparing 4 grams of tetracaine hydrochloride 4% gel an 8% gel was compounded by mistake. How many grams of the 8% gel and gel base must be mixed to get 4 grams of a 4% gel? How many milliliters of 70% ethanol and 20% ethanol must be mixed to prepare 500 ml of 30% ethanol? A diphenhydramine elixir contains 12.5 mg drug in one teaspoon. The volume of oral vehicle that is to be added to 100 ml of this elixir to reduce its strength by one half its original strength is; 6. 90 capsules of Liothyronine (T3) 15 micrograms are to be prepared. The formula calls for a 1:10000…
4 What will be the ideal precipitating agent in gravimetric analysis? Select one: O React to all elements in Alkaline metals, Alkaline earth metals, and Halogens. O Produce a precipitate that is sparingly soluble. React only to the constituents of the atmosphere. O Produce a precipitate of unknown chemical composition after it is ignited.
None
Caffeine Benzoic acid y = 66.391x R2E0.9995 y= 23.633x R? =0:9999 0.5 Injection Volume Injection Volume Aspartame Saccrine y = 6.2204x.. R2 =0.9997 y = 21.43x R² = 0.9891 2.5 0.5 2.5 Injection Volume Injection Volume (Abs) Peak height (Abs) Peak height 2. (Abs) Peak height (Abs) Peak height
A solution contains 0.10 M Sr(NO3)₂ and 0.20 M Bi(NO₂). When solid Na AsO is added to the solution a precipitate forms. What concentration of AsO ³ maintains maximum separation of Sr²+ and Bi³+? Ksp of Sr₂(AsO₂)₂ = 4.29 x 10-1⁹ and BIASO = 4.43 x 10-1⁰ 4 4/2
A 20-mL solution of 0.0659 M AgNO3 was titrated with 20 mL of 0.0509 M NaCl (Ksp = 1.8x10-10). Calculate the pAg of the analyte solution. Express your answer with 3 decimal places.
A tea bag containing 15 grams of tea leaves with 0.7% of caffeine was used in solid-liquid extraction with 200ml of distilled water followed by liquid-liquid extraction using DCM. If 50.0mg of caffeine requires 10 ml of water and 3.0ml of DCM to be dissolved, how much caffeine can be extracted using 70.0ml of DCM? a. 4.8 x 10^-2 b. 5.7 x 10^-2 c. 3.8 x 10^-3 d. 5.8 x 10^-3
The distribution ratio D for an analyte is defined as the ratio of its analytical concentration in two immiscible solvents (organic versus aqueous): D = Corg/Caq Show that the fraction of analyte remained in the aqueous phase after the extraction (from aqueous to organic) is given by the following: Fraction remained = Vaq/(VorgD + Vaq) where Vaq and Vorg are the volume of water and organic solvent used in the extraction, respectively.