Activity 11: Know Your TransformersDirections: Complete the table by using the information in the diagram.V₁ V₂Note the following formula:n₁l₁=n2₂ 1₂:;P= IV1₂(Where: n=no of the coil, I-current, V-voltage, P=power)n=60 turnsV= 120Vn=30 turnshttps://www.engineersgarage.com/articles-basic-electronics-transformers-types1= 2APage 7 of 8Primary windingSecondary winding 46)SECONDARY COILSecondary WindingNo. of CoilsVoltage (V)Current (1)Power (P)Type of TransformerV= 100Vn=5 turnsI= 10 An=20 turnsPrimary WindingPRIMARY COIL||

Given question is related to transformers

Activity 11: Know Your Transformers Directions: Complete the table by using the information in the diagram. Note the following formula: n₁l₁= n₂l₂: V₁ V₂ 1₂ 12₂ : P= IV (Where: n=no of the coil, I-current, V-voltage, P-power) n=60 turns V= 120V n=30 turns https://www.engineergarage.com/articles-basic-electronics-transformers-types/ 1=2A Page 7 of 8 Primary winding Secondary winding 46) SECONDARY COIL Secondary Winding No. of Coils Voltage (V) Current (1) Power (P) Type of Transformer V= 100V n=5 turns I= 10 A n=20 turns Primary Winding PRIMARY COIL ||

Activity 11: Know Your Transformers Directions: Complete the table by using the information in the diagram. Note the following formula: n₁l₁= n₂l₂: V₁ V₂ 1₂ 12₂ : P= IV (Where: n=no of the coil, I-current, V-voltage, P-power) n=60 turns V= 120V n=30 turns https://www.engineergarage.com/articles-basic-electronics-transformers-types/ 1=2A Page 7 of 8 Primary winding Secondary winding 46) SECONDARY COIL Secondary Winding No. of Coils Voltage (V) Current (1) Power (P) Type of Transformer V= 100V n=5 turns I= 10 A n=20 turns Primary Winding PRIMARY COIL ||

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A 50Hz, single phase transformer has a ratio of N2:N1 = 0.2. On full-load, the secondary current is 200A. The resistance and reactance of the primary winding are 0.8 ohm and 4 ohm respectively. The corresponding values for the secondary winding are 0.04 ohm and 0.1 ohm. If the secondary is short circuited, what voltage must be applied to the primary to produce full-load current? What will be the copper loss?
Find out the equivalent inductance for the combination when 2 inductances L1 and L2 are connected in parallel such that their fluxes oppose each other Determine the efficiency of the transformer and find out the value of load at which efficiency will be maximum 3
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(a) Using Faraday's Law as a starting point prove that the maximum operating voltage of a transformer to avoid magnetic saturation is given by the following equation: Q3 Vrms=4.44N.f.Bmax.Ac where: Vrms = maximum rms operating voltage avoiding magnetic saturation N = number of turns in the winding f= electrical frequency (Hz) Bmax = maximum flux density (T) (typically 1.3T for iron) Ac = Iron core cross sectional area (m²) A single phase transformer has the parameters shown on Table Q3 and is connected to a 230 V and 50 Hz AC supply. Sketch the equivalent circuit and using this determine: (b) (i) The Secondary voltage under Open Circuit (Vsoc) (ii) The Secondary voltage, current and power (W) given a 0.6 Q resistive Load. (iii) The efficiency and voltage regulation at this load Through suitable calculations determine whether the size, weight or cost of this transformer could be reduced such that it operated below a maximum flux density of 1.3 T and the current density in both windings…
Q2/A/ What are the conditions for satisfying parallel operation of single phase transformer? Deduce an expression for the load shared by the two transformers in parallel when the transformers have equal voltage ratio? Prove your answer. B/ A 50 KVA, 2300/230 V, 60 11z transformer has a high voltage winding resistance of 0.650 and a low-voltage winding resistance of 0.0065 2. Laboratory tests showed the following results: Open circuit test: V = = 230 V, I =5.7A, P = 190 W Short circuit test: V-41.5 V, I-21.7 A, P-No wattmeter was used. 18 (2) Compute the value of primary voltage needed to give rated secondary voltage when the transformer is connected as a step-up one and is delivering 50 KVA at a power factor of 0.8 lagging. (b) Compute the efficiency under conditions of part (a).
What is the role of transformers in power distribution, and how do they work to step up or step down voltage levels?
Vin V₁ leee V₂ R₂ Vout 1:5 Assume the transformer circuit above is ideal, and that R₁ = 100, R₂ = 400 and 11,rms = 50 A./ Find the rms current, 12,rms, flowing thru the secondary side of the transformer. 12.rms [A]
8. The two winding transformer and the autotransformer of the circuit shown in Figure are ideal. Determine the conducting and transformed currents of auto transformer. N1=200 NBC=20 N2=100 NBA=30 10A B 200 V 50,Hz N1 : N2 lellll
Give and explain, any five practical applications of transformers.200 words
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In Transformers: a. What is the relationship between the turns ratio and the primary to secondarycurrent ratio ? b. What is the relationship between the turns ratio and the primary and secondaryvoltage ratio? c. What can you conclude about the relationship in the values of primary andsecondary apparent power?