Acetaldehyde + NADH + H+ → Ethanol + NAD+How is the inhibition constant for this gotten? Determine the inhibition constant(s) of AMP? [AMP]=0[AMP]=1 mM [AMP]=2 mM [AMP]=3 mM [AMP]=4 mM [AMP]=5 mM[CH;CHO]VoVoVoVoVoVo1.000.0960.0490.0330.0240.0200.0161.500.1280.0650.0430.0330.0260.0222.500.1750.0890.0590.0450.0360.0305.000.2380.1220.0820.0610.0490.04150y = 47.5837x + 14.4554R? = 0.9989[AMP] = 5 mMy = 37.2228x + 13.0690R? = 0.9991[AMP] = 5 mM[AMP] = 4 mM40y = 31.5867x + 9.7472R? = 0.9986[AMP] = 3 mM[AMP] = 4 mMy = 22.6680x + 7.8306R? = 0.9991[AMP] = 2 mM30[AMP] = 3 mMy = 15.2885x + 5.1429[AMP] = 1 mMR? = 1.000020[AMP] = 2 mMy = 7.7837x + 2.6255R? = 1.0000[AMP] = 0 mM[AMP] = 1 mM10(AMP] = 0 mM-0.500-0.300-0.1000.1000.3000.5000.7001/[S]

The enzyme is a biomolecule that catalyzes the reaction by binding to the…

Answered: Acetaldehyde + NADH + H+ → Ethanol +…

Acetaldehyde + NADH + H+ → Ethanol + NAD+ How is the inhibition constant for this gotten? Determine the inhibition constant(s) of AMP?

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Question

Acetaldehyde + NADH + H⁺ → Ethanol + NAD⁺

^{How is the inhibition constant for this gotten? Determine the inhibition constant(s) of AMP?}

[AMP]=0
[AMP]=1 mM [AMP]=2 mM [AMP]=3 mM [AMP]=4 mM [AMP]=5 mM
[CH;CHO]
Vo
Vo
Vo
Vo
Vo
Vo
1.00
0.096
0.049
0.033
0.024
0.020
0.016
1.50
0.128
0.065
0.043
0.033
0.026
0.022
2.50
0.175
0.089
0.059
0.045
0.036
0.030
5.00
0.238
0.122
0.082
0.061
0.049
0.041
50
y = 47.5837x + 14.4554
R? = 0.9989
[AMP] = 5 mM
y = 37.2228x + 13.0690
R? = 0.9991
[AMP] = 5 mM
[AMP] = 4 mM
40
y = 31.5867x + 9.7472
R? = 0.9986
[AMP] = 3 mM
[AMP] = 4 mM
y = 22.6680x + 7.8306
R? = 0.9991
[AMP] = 2 mM
30
[AMP] = 3 mM
y = 15.2885x + 5.1429
[AMP] = 1 mM
R? = 1.0000
20
[AMP] = 2 mM
y = 7.7837x + 2.6255
R? = 1.0000
[AMP] = 0 mM
[AMP] = 1 mM
10
(AMP] = 0 mM
-0.500
-0.300
-0.100
0.100
0.300
0.500
0.700
1/[S]

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