AаBBсс X АаBbСс State phenotype ratios with allele symbols where: A_ = Dominant phenotype; aa = recessive phenotype A. What are the expected genotypic classes / fractions? B. What are the expected phenotypic classes / fractions?
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![AаBBсс X АаBbCс
State phenotype ratios with allele symbols where:
A_ = Dominant phenotype; aa = recessive phenotype
A. What are the expected genotypic classes / fractions?
B. What are the expected phenotypic classes / fractions?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F263d6acc-03b4-45b5-8ce2-d676aa9ac999%2Fdd88f0e8-5440-499d-a46d-534a15f52288%2Fmpes7_processed.png&w=3840&q=75)
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- Please consider the pedigree below. There are no cases of false paternity. I B II A 2 3 III AB (A IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the ABO and H loci?A is dominant over a and B is dominant over b. Genes A/a and B/b assort independently. The parental cross (P) is between true- breeding (homozygous) strains (AA bb x aa BB). The resulting F1 offspring would be [Select ] A F1 x F1 cross gives the F2 generation. The ratio of phenotypes in the F2 generation can be described as [ Select ] In the phenotypic ratio, what number refers to individuals that are: dominant for both traits? [ Select ] recessive for both traits? [Select ] To what phenotypes do the "3"s in the ratio refer? [ Select ] > >Explain the pattern of inheritance and write in the genotypes of the numbered individuals. Indicate possible patterns of inheritance for the RARE traits shown in each of the 4 pedigrees below (a-d). Indicate which individuals are definitely heterozygous and possibly heterozygous (give probability). If individual bIII-1 marries individual bIII-6 what phenotypic ratio would you expect among their offspring?
- If one human parent is heterozygous for blood type A (IAi), and the second parent is heterozygous for blood type B (IBi), what are the expected phenotypic ratios in their children? a. 1/4 with blood type AB, 1/4 with blood type A, 1/4 with blood type B, and 1/4 with blood type O b. 1/4 with blood type A (IAi), 1/2 with blood type AB (IAIB), and 1/4 with blood type B (IBi) c. 1/2 with blood type AB (IAIB), and 1/2 with blood type O (ii) d. 1/2 with blood type A (IAi), and 1/2 with blood type B (IBi) e. 1/2 with blood type A (IAi), and 1/2 with blood type O (ii)Write the number of different kinds of phenotypes,excluding sex, you would see among a large numberof progeny from an F1 mating between individuals ofidentical genotype that are heterozygous for one ortwo genes (that is, Aa or Aa Bb) as indicated. No geneinteractions means that the phenotype determined byone gene is not influenced by the genotype of theother gene.a. One gene; A completely dominant to a.b. One gene; A and a codominant.c. One gene; A incompletely dominant to a.d. Two unlinked genes; no gene interactions; Acompletely dominant to a, and B completelydominant to b.e. Two genes, 10 m.u. apart; no gene interactions; Acompletely dominant to a, and B completely dominant to b.f. Two unlinked genes; no gene interactions; A anda codominant, and B incompletely dominant to b.g. Two genes, 10 m.u. apart; A completely dominantto a, and B completely dominant to b; and withrecessive epistasis between aa and the alleles ofgene B.h. Two unlinked duplicated genes (that is, A and Bperform…A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couples children should have a widow's peak and a hitchhiker's thumb? 3/8 1/4 1/2 3/4 0 A2)The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and has no hitchhikers thumb. What fraction of this couple's children should have no widow's peak and a hitchhiker's thumb? 3/8 0 1/4 1/2 1/8
- A1) The allele for widows peak (H) is dominant for the allele for no widows peak (h). At a different gene locus, the allele for hitchhikers thumb (D) is dominant to the allele for non-hitchhikers thumb (d). A man is heterozygoous for the traits and marries a woman who has no widows peak and is heterozygous for hitchhikers thumb. What fraction of this couple's children should have no widow's peak and no hitchhiker's thumb? 1/4 1/8 1/2 3/8 3/4 A2)Using the forked line method, determine the phenotypic ratio of a trihybrid cross between AaBbCc X AaBBCC. What proportion of offspring will have the dominant phenotype for A, B, and C? 1/8 1/4 1/16 3/4 1/2 A3) How many different offspring genotypes are expected in a trihybrid cross between parents heterozygous for all three traits when the traits behave in a dominant and recessive pattern? How many phenotypes? 8 genotypes; 27 phenotypes 27 genotypes; 8 phenotypes 16 genotypes; 64 phenotypes 64 genotypes; 16 phenotypesThe petal color of a species of flowers is inherited along Mendelian ratios. A cross of two plants with red flowers produces 1,068 plants with red flowers and 390 plants with yellow flowers. A. Propose a model to explain the inheritance of red and yellow flowers. B. Determine the probability of producing a plant with yellow flowers when a heterozygous plant with red flowers is crossed with a homozygous plant with yellow flowers. B I U 三 三 of 22 Answered tv MacBook Air 吕口 F3 D00 F4 # $ & 3 4 5 6 7 Q W E YIn addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.
- Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)(1) * D pols Add-ons Help Last edit was 27 minutes ago ext Calibri 12 BIUA + D田 。 三 三 三▼三 4 5 | 6 L 14. For the following F2 phenotype data, calculate the chi-squared value, determine the p value using the chart above, and explain whether the data follows Mendelian patterns of inheritance. a. Full pods 882, Constricted pods 299 b. Violet flowers = 705, White flowers = 224In chickens the dominant gene (S) produces pea-shaped crest and its recessive allele (s) simple crest.The Andalusian condition (AA *) is an intermediate expression of the genes for black (A) and white (A *) From the following cross between two Andalusian birds-Heterozygous Pea Determine the PHENOTYPIC RATIO OF THEIR DESCENDANTS. 1. 3/4 Pea Black and 1/4 Simple White 2. 3/16 Black Pea, 1/16 Simple Black, 3/16 Andalusian Pea, 1/16 Simple Andalusian, 3/16 White Pea and 1/16 Simple White 3. 9/16 Simple Black, 3/16 Andalusian Pea, 3/16 Simple White and 1/16 Simple White 4. 3/16 Black Pea, 1/16 Simple Black, 6/16 Andalusian Pea, 2/16 Andalusian Simple, 3/16 White Pea and 1/16 White Simple
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