AAA /pc's A4. CH3 CM3 (excess] Brz CHLOH AA

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What are the chemical structures of the following missing compounds?

AAA
/pc's
A4.
CH3 CM3
(excess]
Brz
CHLOH AA <Mylether
CH
CHSO6zBr
mono substiti ko alchol.)
MaNH2
B3 NNH BB
Dz
2q
H2O, HeSO4
B4
A
в кном
C
D
Teq
Cold
473804
Br2
если
AB
BA
Dz Naz
CH₂ Br
BB
Lindlar Cat. W
E
(H2/P-2) D3 LNH Du
reductum
(ROS) hot
KMnO4
E2
Reduction
(mild cond)
F3
H/OH
CH3 MgBr F2E
KMnO4
F
oxid.
CH3 Mg Br
HLOH
E3
екзенгви
G2
Hz/PS
KMnO4
hot
2 G3
Brz
H
excass
त
Tea
I
KM 12
Gold
Hott
Oxymer/
demo.
HOW
ber.
Hyorid.
H3
1:2
Three compounds A, B, and C all have the formula C6H10. All three compounds rapidly
decolorize bromine in CC14; all three are soluble in cold concentrated sulfuric acid.
Compound A has an absorption in its IR spectrum at about 3300 cm, but compounds B
and C do not. Compounds A and B both yield hexane when they are treated with excess
hydrogen in the presence of a platinum catalyst. Under these conditions C absorbs only
one molar equivalent of hydrogen and gives a product with the formula C6H12. When A is
oxidized with hot basic potassium permanganate and the resulting solution acidified, the
only organic product that can be isolated is CH3(CH2) 3CO₂H. Similar oxidation of B
gives only CH3CH2CO₂H, and similar treatment of C gives only HO₂C(CH2) CO₂H.
What are the structure for A, B, and C?
Starting with 2-methylpropene and using any other needed reagents, outline a synthesis
of each of the following:
a. (CH3),COH
b. (CH3),CBr
(CH3)2
c. (CH),C(OH)CH₂CI
Transcribed Image Text:AAA /pc's A4. CH3 CM3 (excess] Brz CHLOH AA <Mylether CH CHSO6zBr mono substiti ko alchol.) MaNH2 B3 NNH BB Dz 2q H2O, HeSO4 B4 A в кном C D Teq Cold 473804 Br2 если AB BA Dz Naz CH₂ Br BB Lindlar Cat. W E (H2/P-2) D3 LNH Du reductum (ROS) hot KMnO4 E2 Reduction (mild cond) F3 H/OH CH3 MgBr F2E KMnO4 F oxid. CH3 Mg Br HLOH E3 екзенгви G2 Hz/PS KMnO4 hot 2 G3 Brz H excass त Tea I KM 12 Gold Hott Oxymer/ demo. HOW ber. Hyorid. H3 1:2 Three compounds A, B, and C all have the formula C6H10. All three compounds rapidly decolorize bromine in CC14; all three are soluble in cold concentrated sulfuric acid. Compound A has an absorption in its IR spectrum at about 3300 cm, but compounds B and C do not. Compounds A and B both yield hexane when they are treated with excess hydrogen in the presence of a platinum catalyst. Under these conditions C absorbs only one molar equivalent of hydrogen and gives a product with the formula C6H12. When A is oxidized with hot basic potassium permanganate and the resulting solution acidified, the only organic product that can be isolated is CH3(CH2) 3CO₂H. Similar oxidation of B gives only CH3CH2CO₂H, and similar treatment of C gives only HO₂C(CH2) CO₂H. What are the structure for A, B, and C? Starting with 2-methylpropene and using any other needed reagents, outline a synthesis of each of the following: a. (CH3),COH b. (CH3),CBr (CH3)2 c. (CH),C(OH)CH₂CI
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