Grain detection 0.8 Peak To Valley Histogram 2.5 unit/div 30 10 20 30 nm Peak to Valley Zoum: 100% 48 12 I nm D3 40 30 20 10 0 VY 0.4 0.8 1.2 1.6 μη Zoom: 100% +x - I DE Line Profile: Red nm 30 20 10 - 224 1:1 Angle (deg): I 0 0 0.4 0.8 1.2 1.6 2 μm Cursor Red AX(μm) 0.047 AY(nm) 18.405 Angle(deg) 21.437 Power Spectrum: Red - 224 μm³ 1.6E-5 1.2E-5 8E-6 4E-6 0 что 0 20 40 60 1/μm
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- . Experimental data mass (g) and volume (mL) of a substance was gathering, recorded, and plotted in Figure 1. a. Correctly la bel the graph axis (include units). b. The equation for the trendline (y = mx + b) is displayed on the graph. Which variable, in the equation, equals the density of the substance? A1 feMass B D Mass Volume 2. 1,8 2,19 Mass vs. volume 3 3,15 4,08 4,13 5,57 7. 6,7 8,34 6. y= 0,794x-0.064 8 6. 10 11. 2 4. 10 13 14 15 Figure 1: Plotting of Mass vs. Volume of a Substance. bttps://www.chemisalforums.com/index.php?toric=69575.0 Life University CHM 111 March 2021 Default Page Style English (USA)A titrimetric method for the determination of calcium in limestone was tested by analysis of an NIST limestone containing 30.15% CaO. The mean result of four analyses was 30.26% CaO, with a standard deviation of 0.085%. By pooling data from several analyses, it was established that s = 0.094% CaO.a. Do the data indicate the presence of a systematic error at the 95% confidence level?b. Do the data indicate the presence of systematic error at the 95% confidence level if no pooled value for s was available?Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any âdriftâ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
- observation/inferenceMolarity trail 1 0.0366 trail 2 0.0373 trail 3 0.0370 Calculate the standard deviation. Calculate the Relative Standard deviation of molarity to 3 sig figs.Can you please fill the rest of tghe data based on the on inforamtion you have and answer Average concentratuon of NaOH Standard deviation of concentration
- Trial Mass (g) 1 48.8839 2 49.0099 3 49.1121 4 48.9342 5 49.0338 6 48.7798 Calculate mean and standard deviation in the correct number of sigfigsCalculate the bulk density of a 130 cm3 soil sample with an oven-dry weight of 160 gStandardization of EDTA Solution Weight of pure CaCO3: 0.2517 g % Purity of CaCO3: 98.0% Total volume of standard CaCO3 solution: 250.00 mL Trial 1 2 3 Volume of standard CaCO3 solution (ml) 25.00 25.00 25.00 Final Volume Reading EDTA (ml) 24.30 47.95 24.72 Initial Volume Reading EDTA (ml) 0.00 24.30 0.20 Volume of titrant, EDTA (ml) Molarity of EDTA (M)
- ■ True or False: in a TOF analyzer, a fragment of low mass reaches the detector first ▪ In GCMS when we know what analytes we are measuring we use not know what analytes are in the sample we use than scan. ▪ A) Scan; SIM ■ B)SIM; scan • C) SIM; SIM mode. When we do mode. SIM allows greater sensitivity#9: This unknown contains 51.90 % C and 9.80 % H by mass with the remainder being an unknown element (you have to figure out what element). 100- Base 80 60 90 Relative Intensity 100 TRANSNETTANCE 40 20- O 4000 10 20 3000 30 peak 656 50 40 m/z REVENUTER 60 1300 peak 094 92-37= 90-35= C) 70 80 1000 90Calculate the standard deviation of the four trials below. Trial 1: 49.59 grams Trial 2: 51.25 grams Trial 3: 49.78 grams Trial 4: 50.19 grams