6) What is the density of NaCl given thatand rci = 181pm.Show your calculations below.rNa+ = 102pmHint: Edge length of an unit cell of NaCl, d = 2rci +2rNa+, Volume = d³Mass of NaCl unit cell = (58.54g/formula unit) x (# of 'units of NaCl' in a unit cell)6.022 x 1023 units/ formula unitDensity = mass/volume

Answered: Image /qna-images/answer/53d72ae0-7892-4ef8-8f43-faaed37d7408.jpg

6) What is the density of NaCl given that and rci = 181pm. Show your calculations below. rNa+ = 102pm Hint: Edge length of an unit cell of NaCl, d = 2rcr + 2rNa*, Volume = d³ Mass of NaCl unit cell = (58.54g/formula unit) x (# of 'units of NaCl’ in a unit cell) 6.022 x 1023 units/ formula unit Density = mass/volume

6) What is the density of NaCl given that and rci = 181pm. Show your calculations below. rNa+ = 102pm Hint: Edge length of an unit cell of NaCl, d = 2rcr + 2rNa*, Volume = d³ Mass of NaCl unit cell = (58.54g/formula unit) x (# of 'units of NaCl’ in a unit cell) 6.022 x 1023 units/ formula unit Density = mass/volume

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Thermodynamics and enthalpy Data: M(Pb) = 207 g mol" AmeltH°(Pb) = 4.8 kJ·mol" AvapH°(Pb) = 179.5 kJ·mol" Cp (Pb, liquid) = 32.4 J mol"' K-' Tmelt = 327°C Tvap = 1749°C Cp (Pb, solid) = 23.6 J mol·' K'' Let's consider the conversion of lead (Pb) in the gas phase at 1749 °C into lead in the solid state at 250 °C under the standard pressure P° = 1 bar. a. Calculate the standard molar enthalpy for this reaction.
Rank the compounds below from lowest to highest viscosity based on their structures. (Hint: hydrogen bonds formed between molecules with N-H groups are weaker than those formed between molecules with O-H groups.) 1-propanol, CH3CH2CH2OH propane, CH3CH2CH3 propanal, CH3CH2CH=O 1-propanamine, CH3CH2CH2NH2
Determine the heat of dissolution, in kJ/mol, of 0.250 mol C2 having a specific heat of 0.82 J/g °C. A 9 g sample of C2 was placed in calorimeter with water weighing 130 g. The initial temperature of the system was 18.6 °C and was allowed to reach thermal equilibrium at a temperature of 23.1 °C. Assume that the calorimeter is a perfect insulator. Report answer with 3 significant figures.
(a) Would you expect the viscosity of n-pentane,CH3CH2CH2CH2CH3, to be larger or smaller than the viscosityof n-hexane, CH3CH2CH2CH2CH2CH3? (b) Wouldyou expect the viscosity of neopentane, (CH3)4C, to besmaller or larger than the viscosity of n-pentane? (See Figure11.6 to see the shapes of these molecules.)
27. Substances A to E below are listed with several of their properties. The identities of the substance are identified in random order below: Substanc Melting Pt. (°C) e iron, ethane, ethanol, sodium nitrate, graphite In the sixth column, classify each substance as either a polar covalent compound, non-polar covalent compound, ionic compound, metallic solid, or network covalent solid. Then, identify the substance in the last column. (10) A B C D E 308 -114 1538 -182 Boiling Solubility in H₂O Pt. (°C) 380 78 3456 2862 -88 Soluble Soluble Electrical conductivity as: Solid/liquid/ solution Yes/Yes/Yes No/No/No Insoluble No/-/- Insoluble Yes/Yes/- Insoluble No/No/- Type of substance: Identity of substance:
The following information is given for cobalt at 1atm: boiling point = 3097 °C Hvap(3097 °C) = 389 kJ/mol melting point = 1495 °C Hfus(1495 °C) = 15.5 kJ/mol specific heat solid= 0.418 J/g°C specific heat liquid = 0.686 J/g°C What is H in kJ for the process of freezing a 46.3 g sample of liquid cobalt at its normal melting point of 1495 °C._____ kJ