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Linear molecule-larger surface area enhanoes intermoleoular oontaot and inoreases dispersion foroe. n-Pentane (CH12) bp = 309.4 K Spherical molecule-emaller surface area diminishes intermolecular oontact and deoreases dispersion foroe. Neopentane (C;H12) bp = 282.7 K A Figure 11.6 Molecular shape affects

Linear molecule-larger surface area enhanoes intermoleoular oontaot and inoreases dispersion foroe. n-Pentane (CH12) bp = 309.4 K Spherical molecule-emaller surface area diminishes intermolecular oontact and deoreases dispersion foroe. Neopentane (C;H12) bp = 282.7 K A Figure 11.6 Molecular shape affects

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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(a) Would you expect the viscosity of n-pentane,
CH3CH2CH2CH2CH3, to be larger or smaller than the viscosity
of n-hexane, CH3CH2CH2CH2CH2CH3? (b) Would
you expect the viscosity of neopentane, (CH3)4C, to be
smaller or larger than the viscosity of n-pentane? (See Figure
11.6 to see the shapes of these molecules.)

Linear molecule-larger surface area enhanoes intermoleoular oontaot and inoreases dispersion foroe. n-Pentane (CH12) bp = 309.4 K Spherical molecule-emaller surface area diminishes intermolecular oontact and deoreases dispersion foroe. Neopentane (C;H12) bp = 282.7 K A Figure 11.6 Molecular shape affects
Transcribed Image Text:Linear molecule-larger surface area enhanoes intermoleoular oontaot and inoreases dispersion foroe. n-Pentane (CH12) bp = 309.4 K Spherical molecule-emaller surface area diminishes intermolecular oontact and deoreases dispersion foroe. Neopentane (C;H12) bp = 282.7 K A Figure 11.6 Molecular shape affects
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