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A4.2- Develop the column interaction diagram for a tied short column, shown in Figure 2. Given: f'c = 35 MPa fy = 400 MPa Longitudinal bars: 8-35M Ties: 10M@ 300 Clear cover to the ties: 40mm T 500 mm 500 mm Figure 2 , MPa 25 P₁ = 0.05 20 20 15 2/8° 10 5 P₁ = 0.04 P₁ = 0.03 P=0.02 P₁ = 0.01 fs/fy .0 Y = 0.70 b f = 25 MPa yh fy = 400 MPa h fs/fy = 0.5 fs/fy = 1.0 1 2 3 5 6 M, MPa Agh

A4.2- Develop the column interaction diagram for a tied short column, shown in Figure 2. Given: f'c = 35 MPa fy = 400 MPa Longitudinal bars: 8-35M Ties: 10M@ 300 Clear cover to the ties: 40mm T 500 mm 500 mm Figure 2 , MPa 25 P₁ = 0.05 20 20 15 2/8° 10 5 P₁ = 0.04 P₁ = 0.03 P=0.02 P₁ = 0.01 fs/fy .0 Y = 0.70 b f = 25 MPa yh fy = 400 MPa h fs/fy = 0.5 fs/fy = 1.0 1 2 3 5 6 M, MPa Agh

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter12: Electric Current And Related Variables In Engineering
Section12.2: Electrical Circuits And Components
Problem 6BYG
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A4.2- Develop the column interaction diagram for a tied short column, shown in Figure 2. Given: f'c = 35 MPa fy = 400 MPa Longitudinal bars: 8-35M Ties: 10M@ 300 Clear cover to the ties: 40mm T 500 mm 500 mm Figure 2
Transcribed Image Text:A4.2- Develop the column interaction diagram for a tied short column, shown in Figure 2. Given: f'c = 35 MPa fy = 400 MPa Longitudinal bars: 8-35M Ties: 10M@ 300 Clear cover to the ties: 40mm T 500 mm 500 mm Figure 2
, MPa 25 P₁ = 0.05 20 20 15 2/8° 10 5 P₁ = 0.04 P₁ = 0.03 P=0.02 P₁ = 0.01 fs/fy .0 Y = 0.70 b f = 25 MPa yh fy = 400 MPa h fs/fy = 0.5 fs/fy = 1.0 1 2 3 5 6 M, MPa Agh
Transcribed Image Text:, MPa 25 P₁ = 0.05 20 20 15 2/8° 10 5 P₁ = 0.04 P₁ = 0.03 P=0.02 P₁ = 0.01 fs/fy .0 Y = 0.70 b f = 25 MPa yh fy = 400 MPa h fs/fy = 0.5 fs/fy = 1.0 1 2 3 5 6 M, MPa Agh
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