A. Standardization of NaOH Solution Chemical Reactions: Molecular Equation: HCl(aq) + NaOH(ag) –→ NaCl(aq) + H,O(1) Net Ionic Equation: H'(aq) + OH(aq) · H,O(1) Details Trial 1 Trial 2 Trial 3 Molarity of HC1 Standard Solution Volume (mL) HC1 Standard Solution No. of mmoles HCI = No. of mmoles H No. of mmoles OH reacted with HCl No. of mmoles NaOH reacted with HCi Final Reading (mL) NaOH Buret Initial Reading (mL) NaOH Buret Volume (mL) NaOH Solution Delivered Molarity of NaOH 0.1024 25.00 25.00 25.00 22.17 22.15 22.28 0.05 0.05 0.10 0.1157 0.1158 0.1154

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Please help me how to calculate this. All about titration. even the trial 1 will do I can do trial 2 and 3. I just need to learn how to do it. thanks

A. Standardization of NaOH Solution
Chemical Reactions: Molecular Equation: HCl(ag) + NaOH(aq)
NaCl(aq) + H,о(O
H,O(1)
-
Net Ionic Equation: H(ag) + OH(aq)
-
Details
Trial 1
Trial 2
Trial 3
Molarity of HCl Standard Solution
Volume (mL) HC1 Standard Solution
No. of mmoles HCl = No. of mmoles H
No. of mmoles OH reacted with HCí
No. of mmoles NaOH reacted with HCi
Final Reading (mL) NAOH Buret
Initial Reading (mL) NAOH Buret
Volume (mL) NAOH Solution Delivered
Molarity of NaOH
0.1024
25.00
25.00
25.00
22.28
0.10
22.17
22.15
0.05
0.05
0.1157
0.1158
0.1154
Transcribed Image Text:A. Standardization of NaOH Solution Chemical Reactions: Molecular Equation: HCl(ag) + NaOH(aq) NaCl(aq) + H,о(O H,O(1) - Net Ionic Equation: H(ag) + OH(aq) - Details Trial 1 Trial 2 Trial 3 Molarity of HCl Standard Solution Volume (mL) HC1 Standard Solution No. of mmoles HCl = No. of mmoles H No. of mmoles OH reacted with HCí No. of mmoles NaOH reacted with HCi Final Reading (mL) NAOH Buret Initial Reading (mL) NAOH Buret Volume (mL) NAOH Solution Delivered Molarity of NaOH 0.1024 25.00 25.00 25.00 22.28 0.10 22.17 22.15 0.05 0.05 0.1157 0.1158 0.1154
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