Determine the pH of a buffer solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The pKb of NH, is 4.75. Complete Parts 1-3 before submitting your answer. < PREV NEXT > Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. 0.25 + x [2x]² [0.15 - 2x] 0.25 - x [0.25 + x] 4.75 1 Kb = [0] [0.25 -x] 1.78 x 10.5 [0.25] [0.25 + 2x] 5.62 x 10-1⁰ 2 [0.15] [0.25 - 2x] 1.79 × 10.1⁹ [4.75] [0.15 + x] 3 [x] [0.15 -x] RESET [2x] [0.15 + 2x]
Determine the pH of a buffer solution by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The pKb of NH, is 4.75. Complete Parts 1-3 before submitting your answer. < PREV NEXT > Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. 0.25 + x [2x]² [0.15 - 2x] 0.25 - x [0.25 + x] 4.75 1 Kb = [0] [0.25 -x] 1.78 x 10.5 [0.25] [0.25 + 2x] 5.62 x 10-1⁰ 2 [0.15] [0.25 - 2x] 1.79 × 10.1⁹ [4.75] [0.15 + x] 3 [x] [0.15 -x] RESET [2x] [0.15 + 2x]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hello! Would you please help me work through this 3 part question step-by-step? Parts 1 & 2 are attached below as screenshots.
Part 3: Based on your ICE table (Part 1) and the equilibrium expression for Kb (Part 2), determine the pH of the buffer solution.
pH = ( )
Thank you!
![Determine the pH of a buffer solution by constructing an ICE table, writing the
equilibrium constant expression, and using this information to determine the pH.
The pKb of NH, is 4.75. Complete Parts 1-3 before submitting your answer.
3
<
NEXT >
Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb in order
to determine the unknown. Each reaction participant must be represented by one tile. Do not
combine terms.
PREV
0.25 + x
[2x]²
[0.15 - 2x]
0.25 - x
[0.25 + x]
4.75
1
Kb =
[0]
[0.25 -x]
1.78 x 10-5
[0.25]
[0.25 + 2x]
5.62 × 10-1⁰
2
[0.15]
[0.25 - 2x]
1.79 × 10-1⁹
II
[4.75]
[0.15 + x]
3
[x]
[0.15 -x]
RESET
[2x]
[0.15 + 2x]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb426c7ec-0b8d-4059-a97d-2a2739579ea3%2F33152b0e-3ff9-4e5e-b286-67081f26f248%2Fhgr107q_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the pH of a buffer solution by constructing an ICE table, writing the
equilibrium constant expression, and using this information to determine the pH.
The pKb of NH, is 4.75. Complete Parts 1-3 before submitting your answer.
3
<
NEXT >
Based on your ICE table (Part 1) and the definition of Kb, set up the expression for Kb in order
to determine the unknown. Each reaction participant must be represented by one tile. Do not
combine terms.
PREV
0.25 + x
[2x]²
[0.15 - 2x]
0.25 - x
[0.25 + x]
4.75
1
Kb =
[0]
[0.25 -x]
1.78 x 10-5
[0.25]
[0.25 + 2x]
5.62 × 10-1⁰
2
[0.15]
[0.25 - 2x]
1.79 × 10-1⁹
II
[4.75]
[0.15 + x]
3
[x]
[0.15 -x]
RESET
[2x]
[0.15 + 2x]
Transcribed Image Text:Determine the pH of a buffer solution by constructing an ICE table, writing the
equilibrium constant expression, and using this information to determine the pH.
The pKb of NH, is 4.75. Complete Parts 1-3 before submitting your answer.
3
Initial (M)
Change (M)
Equilibrium (M)
|
-2x
A solution is prepared with 0.25 M NH₂ and 0.15 M NH CI. Fill in the ICE table with the
appropriate value for each involved species to determine concentrations of all reactants and
products.
0.15 - 2x
0
1
0.25 + x
NH,(aq)
0.25
0.25 - x
+
0.15
2
H₂O(1)
0.25 + 2x
4.75
0.25 - 2x
3
OH (aq)
+x
0.15 + x
+
-X
NEXT
0.15 - x
NH,(aq)
RESET
+2x
0.15 + 2x
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