Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the mass of starting material required. Complete Parts 1-3 before submitting your answer. NEXT > Sodium acetate (CH3COONa) is added to an existing 500.0 mL solution of 0.200 M CH3COOH to form a buffer with a pH equal to 5.000. Let x represent the concentration of CH3COO in the water after the addition of CH3COONa. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) CH3COOH(aq) + 0 [0] 0.200 1.0 x 10-5 -1.0 x 10-5 -1.8 x 10-5 x+1.0 × 105x-1.0 × 10-5x+1.8 × 10-x-1.8 × 10- [x - 5.00] [500.0] x 1.8 x 10-5 1 [x+1.0 x 10] Question 4 of 23 Ka = [0.200] H₂O(l) [x-1.0 x 10] 2 5.00 Question 4 of 23 Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the mass of starting material required. Complete Parts 1-3 before submitting your answer. [5.00] x + 5.00 < PREV 2 3 NEXT > The value of Ka for CH3COOH is 1.8 x 10-5. Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. [x+1.0 x 105] ■ HgO*(aq) + CH3COO (aq) -5.00 [1.0 x 10⁹] 3 x - 5.00 [x -1.0 x 105] 1.0 x 10⁹ x+1.0 x 109 = 1.8 x 10-5 [1.0 x 105] [x+1.8 x 10-1 RESET [1.8 x 105] -1.0 × 10-⁹ x-1.0 × 10⁹ [x-1.8 x 10³] RESET [x+ 5.00]
Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the mass of starting material required. Complete Parts 1-3 before submitting your answer. NEXT > Sodium acetate (CH3COONa) is added to an existing 500.0 mL solution of 0.200 M CH3COOH to form a buffer with a pH equal to 5.000. Let x represent the concentration of CH3COO in the water after the addition of CH3COONa. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) CH3COOH(aq) + 0 [0] 0.200 1.0 x 10-5 -1.0 x 10-5 -1.8 x 10-5 x+1.0 × 105x-1.0 × 10-5x+1.8 × 10-x-1.8 × 10- [x - 5.00] [500.0] x 1.8 x 10-5 1 [x+1.0 x 10] Question 4 of 23 Ka = [0.200] H₂O(l) [x-1.0 x 10] 2 5.00 Question 4 of 23 Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the mass of starting material required. Complete Parts 1-3 before submitting your answer. [5.00] x + 5.00 < PREV 2 3 NEXT > The value of Ka for CH3COOH is 1.8 x 10-5. Based on your ICE table (Part 1) and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. [x+1.0 x 105] ■ HgO*(aq) + CH3COO (aq) -5.00 [1.0 x 10⁹] 3 x - 5.00 [x -1.0 x 105] 1.0 x 10⁹ x+1.0 x 109 = 1.8 x 10-5 [1.0 x 105] [x+1.8 x 10-1 RESET [1.8 x 105] -1.0 × 10-⁹ x-1.0 × 10⁹ [x-1.8 x 10³] RESET [x+ 5.00]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution
at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the mass of starting material
required. Complete Parts 1-3 before submitting your answer.
NEXT >
Sodium acetate (CH3COONa) is added to an existing 500.0 mL solution of 0.200 M CH3COOH to form a
buffer with a pH equal to 5.000. Let x represent the concentration of CH3COO in the water after the
addition of CH3COONa. Fill in the ICE table with the appropriate value for each involved species to
determine concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
CH3COOH(aq) +
0.200
1.0 x 10-²
-1.0 x 10-5
-1.8 x 10-5
x+1.0 × 105x-1.0 × 10-5x+1.8 × 10-5x-1.8 × 10-
[0]
0
[x - 5.00]
[500.0]
x
1.8 x 10-5
1
[x+1.0 x 10]
Question 4 of 23
Ka =
[0.200]
H₂O(l)
[x-1.0 x 10]
2
Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution
at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the mass of starting material
required. Complete Parts 1-3 before submitting your answer.
5.00
Question 4 of 23
< PREV
2
3
NEXT >
The value of Ka for CH3COOH is 1.8 x 10-5. Based on your ICE table (Part 1) and the definition of Ka, set
up the expression for Ka in order to determine the unknown. Each reaction participant must be represented
by one tile. Do not combine terms.
[5.00]
x + 5.00
[x+1.0 x 105]
■
HạO*(aq) + CH3COO (aq)
-5.00
[1.0 × 10-⁹]
3
x - 5.00
[x -1.0 x 105]
1.0 x 10⁹
x+1.0 x 109
= 1.8 x 10-5
[1.0 x 105]
[x+1.8 x 10 1
RESET
-1.0 × 10-⁹
x-1.0 × 10-⁹
[1.8 x 105]
[x-1.8 x 10³]
RESET
[x+ 5.00]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84d3fdf0-b73f-4040-a051-97beff994827%2Fbc28ebd3-1e0d-4023-a0d8-9eb4e80172b3%2F1gkevoh_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution
at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the mass of starting material
required. Complete Parts 1-3 before submitting your answer.
NEXT >
Sodium acetate (CH3COONa) is added to an existing 500.0 mL solution of 0.200 M CH3COOH to form a
buffer with a pH equal to 5.000. Let x represent the concentration of CH3COO in the water after the
addition of CH3COONa. Fill in the ICE table with the appropriate value for each involved species to
determine concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
CH3COOH(aq) +
0.200
1.0 x 10-²
-1.0 x 10-5
-1.8 x 10-5
x+1.0 × 105x-1.0 × 10-5x+1.8 × 10-5x-1.8 × 10-
[0]
0
[x - 5.00]
[500.0]
x
1.8 x 10-5
1
[x+1.0 x 10]
Question 4 of 23
Ka =
[0.200]
H₂O(l)
[x-1.0 x 10]
2
Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution
at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the mass of starting material
required. Complete Parts 1-3 before submitting your answer.
5.00
Question 4 of 23
< PREV
2
3
NEXT >
The value of Ka for CH3COOH is 1.8 x 10-5. Based on your ICE table (Part 1) and the definition of Ka, set
up the expression for Ka in order to determine the unknown. Each reaction participant must be represented
by one tile. Do not combine terms.
[5.00]
x + 5.00
[x+1.0 x 105]
■
HạO*(aq) + CH3COO (aq)
-5.00
[1.0 × 10-⁹]
3
x - 5.00
[x -1.0 x 105]
1.0 x 10⁹
x+1.0 x 109
= 1.8 x 10-5
[1.0 x 105]
[x+1.8 x 10 1
RESET
-1.0 × 10-⁹
x-1.0 × 10-⁹
[1.8 x 105]
[x-1.8 x 10³]
RESET
[x+ 5.00]

Transcribed Image Text:Determine the quantity of sodium acetate (CH3COONa) needed to create buffer solution
at a particular pH. Do this by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the mass of starting material
required. Complete Parts 1-3 before submitting your answer.
< PREV
1
Based on your ICE table (Part 1) and the equilibrium expression, Ka (Part 2), determine the original mass
of solid CH3COONa added to create this buffer solution.
mNaCH3COO
0
3.6 × 10³
0.360
5.9 x 10³
30
4.3 x 10³
21
2
=
43
g
11
3
15
RESET
59
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