A biologist looked at the relationship between number of seeds a plant produces and the percent ofthose seeds that sprout. The results of the survey are shown below.49 40 54 56 625847 6059Seeds Produced 56Sprout Percent 49 | 58.5 | 50 | 51.5 | 54.5 636252Round to 2 decimal places.a. Find the correlation coefficient: r =b. The null and alternative hypotheses for correlation are:Họ: ?v = 0The p-value Is:(Round to four decimal places)t Use a level of significance of a = 0.05 to state the conclusion of the hypothesis test in thecontext of the study.O There is statistically insignificant evidenceseeds will have seeds with a lower sprout rate than a plant that produces fewer seeds.conclude that a plant that produces moreO There is statistically significant evidence to conclude that a plant that produces moreseeds will have seeds with a lower sprout rate than a plant that produces fewer seeds.O There is statistically significant evidence to conclude that there is a correlation betweenthe number of seeds that a plant produces and the percent of the seeds that sprout.Thus, the regression line is useful.O There is statistically insignificant evidence to conclude that there is a correlationbetween the number of seeds that a plant produces and the percent of the seeds thatsprout. Thus, the use of the regression line is not appropriate.d. p(Round to two decimat places)e. Interpret r:O There is a 47% chance that the regression line will be a good predictor for the percent ofseeds that sprout based on the number of seeds produced.There is a large variation in the percent of seeds that spreut, bt if ynI only look atplants that pretuce a fiet anter of sds this variatn en avera ISTdued tyesc80F3F7%232$67QWtabTYAScaps lockFGshiftCVNcontroloptioncommand* 00B* LO plants that produce a fixed number of seeds, this variation on average is reduced by47%.47% of all plants produce seeds whose chance of sprouting is the average chance ofsprouting.O Given any group of plants that all produce the same number of seeds, 47% of all ofthese plants will produce seeds with the same chance of sprouting.f. The equation of the linear regression line is:(Please show your answers to two decimal places)g. Use the model to predict the percent of seeds that sprout if the plant produces 56 seeds.(Please round your answerr to the nearest whole number.)Percent sprouting =h. Interpret the slope of the regression line in the context of the question:O For every additional seed that a plant produces, the chance for each of the seeds tosprout tends to decrease by 0.50 percent.O The slope has no practical meaning since it makes no sense to look at the percent of theseeds that sprout since you cannot have a negative number.O As x goes up, y goes down.1. Interprêt the y-intercept in the context of the question:O The best prediction for a plant that has 0 seeds is 82.4 percent.O The y-intercept has no practical meaning for this study.O If plant produces no seeds, then that plant's sprout rate will be 82.4.O The average sprouting percent is predicted to be 82.4.Hint Helpful Virten on the tinsar itepression tine 1escF3DIIF72324&248.QWtabYSFcaps lockCVNBA

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a. Find the correlation coefficient: f = Round to 2 decimal places. b. The null and alternative hypotheses for correlation are: Hạ: [?v] The p-value Is: (Round to four decimal places) C Use a level of significance of o context of the study. 0.05 to state the COntlusion of the hypothesis test in the

a. Find the correlation coefficient: f = Round to 2 decimal places. b. The null and alternative hypotheses for correlation are: Hạ: [?v] The p-value Is: (Round to four decimal places) C Use a level of significance of o context of the study. 0.05 to state the COntlusion of the hypothesis test in the

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (H) at a significance level of a = Ho: P1 = P2 Ha: P₁ P2 You obtain a sample from the first population with 122 successes and 438 failures. You obtain a sample from the second population with 63 successes and 304 failures. test statistic = p-value = [three decimal accuracy] 0.001. [four decimal accuracy]
Use the departure delay times and the arrival delay times to test the claim that there is a correlation between departure delay times and arrival delay times. Test for rank correlation with a 0.05 significance level. Click here to view the flight delay data. Click here to view the critical values of Spearman's rank correlation coefficient. Flight delay data .... Determine the null and alternative hypotheses for this test. Choose the correct answer below. O A. Hg: Ps =0 Departure Delay Arrival Departure Delay Arrival O B. Ho: Ps #0 H: Ps = 0 Departure Delay Arrival H: Ps #0 Delay Delay Delay - 36 -7 11 14 OC. Ho:r 0 H:r=0 O D. Ho: r =0 H:rg 40 -21 15 25 -33 10 -32 Determine the the correlation coefficient. - 5 32 13 4 12 16 -23 (Round to three decimal places as needed.) 3 14 -38 60 28 13 3 13 149 111 Determine the critical value(s) of the correlation coefficient, -38 -7 -35 - 3 -21 -23 23 - 2 -10 14 (Round to three decimal places as needed. Use a comma to separate answers as needed.)…
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
The accompanying table lists the ages of acting award winners matched by the years in which the awards were won. Construct a scatterplot, find the value of the linear correlation coefficient r, and find the P-value of r. Determine whether there is sufficient evidence to support a claim of linear correlation between the two variables. Should we expect that there would be a correlation? Use a significance level of = 0.05. E Click the icon to view the ages of the award winners. Construct a scatterplot. Choose the correct graph below. OA. OB. Oc. OD. 70- 70- Q 70- 70- ... ++++++ 20 - 20 Best Actress (years) 20- 70 20 Best Actress (years) 20- 20 Best Actress (years) 70 20 Best Actress (years) 70 70 Best Actresses and Best Actors Best Actress 27 29 30 58 33 34 46 30 62 22 44 51 D Best Actor 44 36 38 44 53 46 56 49 41 52 44 33
(i) State the hyptheses. (ii) Sketch a scatter plot tat best represents the data. (iii) Compute the value of the correlation coefficient. Round the answer to at least three decimal places. (iv) Find the P-value. Round the answer to at least four decimal places. Test the significance of r at α=0.05. Determine whether to reject or not reject the null hypothesis.
5.32 Fuel efficiency of manual and automatic cars, Part I: Do these data provide strong evidence of a difference between the average fuel efficiency of cars with manual and automatic transmissions in terms of their average city mileage? Assume that conditions for inference are satisfied. City MPG, Automatic City MPG, Manual Mean 16.12 19.85 SD 3.58 4.51 n 26 26 The test statistic is:The p-value is:
Test the claim that the mean GPA of night students is significantly different than 3.3 at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p0.825 H p 3.3 H p 0.825 H p <3.3 H:p 3.3 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.33 with a standard deviation of 0.04 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than 2.6 at the 0.05 significance level. The null and alternative hypothesis would be: Но: д — 2.6 Нo:р 3 0.65 Но: р %—D 0.65 Но:н H:р > 2.6 Н:p#0.65 Hi:p > 0.65 Н:д < 2.6 H:д 2 2.6 H:р<0.65 - 2.6 Ho:µ 2.6 Но:р 0.65 = = The test is: right-tailed left-tailed two-tailed Based on a sample of 65 people, the sample mean GPA was 2.63 with a standard deviation of 0.05 The test statistic i: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Next Question Assume a significance level of a = 0.05 and use the given information to cd d (b) below. Original claim: More than 43% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0443. ..... a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. A. Fail to reject Ho because the P-value is greater than x. B. Reject H, because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 43%. B. There is not sufficient evidence to support the…
Using a sample that has n=50 pair of data, we get a correlation coefficient r=-0.269 for the following null and alternative hypotheses determine and compute the test statistic value: HO: p=0 H1: pe 0 O a t=7.51 O b. z=7.51 O o.z=-0. 16 Odt=-1.08