A Y-connected balanced three-phase generator with an impedance of 0.4+ j0.32 per phase is connected to a Y-connected balanced load with an impedance of 24 + j19 22 per phase. The line joining the generator and the load has an impedance of 0.6+ j0.7 22 per phase. Assuming a positive sequence for the source voltages and that Van = 120/30⁰ V, find: (a) the line voltages, (b) the line currents.

A Y-connected balanced three-phase generator with an impedance of 0.4+ j0.32 per phase is connected to a Y-connected balanced load with an impedance of 24 + j19 22 per phase. The line joining the generator and the load has an impedance of 0.6+ j0.7 22 per phase. Assuming a positive sequence for the source voltages and that Van = 120/30⁰ V, find: (a) the line voltages, (b) the line currents.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

SAP ID =8925
PLEASE SHOW ALL THE STEPS AND THE WAY OF THE SOLUTION , BECAUSE I WANT TO LEARN HOW TO SOLVE, THANK YOU FOR YOUR UNDERSTANDING
A balanced three-phase, negative sequence, Y-connected generator is connected to a three-phase balanced Y-connected load. The generator has an impedance of 1.5-j1.25 Ω/phase. The impedance of the line connecting the generator to the load is 2.5+j1.25 Ω/phase. The phase “B” load voltage is 15∠20 kV. The impedance of each phase of the Y-connected load is 60-j80 Ω/phase. Calculate line voltage VABVAB at the load.
A Y-connected bulamced three-phase generator with un impedunce of 0.4+ j0.3 2 per phase is connected to a Y-connected balanced load with au impedance of 24+j19 2 per phase. The line joining the geucrator and the load has an impedance of 0.6 + j0.7 2 per phase. Assuming a positive sequenee for the source voltages and that Var = 120/30 V. find: (a) the line voltages, (b) the line currents.
Suppose Y-SOURCE WILL BE CONVERTED TO DELTA-SOURCE, solve the required C.
Please solve this problem asap correctly. Need step by step explanation. Wrong solution will get downvote.
Derive an equation for the total instantaneous power absorbed by a balanced three-phase load. Be sure to clearly list any assumptions you make in your derivation.
A three-phase A-connected generator has an inter- nal impedance of 9 + j90 m2/þ. When the load is removed from the generator, the magnitude of the terminal voltage is 13,800 V. The generator feeds a A-connected load through a transmission line with an impedance of 20 + j180 m2/þ. The per-phase impedance of the load is 7.056 + j3.417 N. a) Construct a single-phase equivalent circuit. b) Calculate the magnitude of the line current. c) Calculate the magnitude of the line voltage at the terminals of the load. d) Calculate the magnitude of the line voltage at the terminals of the source.
A balanced three-phase load requires 1.8kW and power factor 0.5. If the line voltage at the terminals of the load is 230 V. the magnitude of line current is: Select one: a. 7.82 A O b. 9.03A O c. 15.65 A O d. 4.51 A
For balanced three-phase Y-A system below, if the voltage increases by 10%, the average power delivered to the load will be O No answer is correct OP=2871 W OP 3744 W OP 4544 W 110/0° Vrms 110-120° V rms 110/120° V rms 252 www 292 292 www 9-j692 9-j692 9-j6 92
The terminal voltage of a 3-φ generator is 19053 V, line-to-line. The load draws a current of 1515 A, leading, with a phase angle of 30o. The total real power, drawn by the load would be:
PLEASE SHOW ALL THE STEPS AND THE WAY OF THE SOLUTION , BECAUSE I WANT TO LEARN HOW TO SOLVE, THANK YOU FOR YOUR UNDERSTANDING