A wastewater treatment plant consists of a primary clarifier and an activated sludge reactor (with recycle) followed by a secondary clarifier. The average inflow of wastewater to the primary clarifier is 14,500 m³/day with a BOD, of 250 mg/L and suspended solids concentration of 300 mg/L. The recirculation ratio in the secondary system is 0.75, with an underflow solids concentration of 12,000 mg/L. Calculate the area required for secondary clarification when the slope of the limiting solids flux line is 0.5 m/h from a plot of solids flux (kg/m²-h) versus solids concentration (kg/m³). The set- tling velocity of the solids at the MLSS concentration of 6500 mg/L is 0.7 m/h.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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10.10 A wastewater treatment plant consists of a primary clarifier and
an activated sludge reactor (with recycle) followed by a secondary
clarifier. The average inflow of wastewater to the primary clarifier
is 14,500 m³/day with a BOD, of 250 mg/L and suspended solids
concentration of 300 mg/L. The recirculation ratio in the secondary
system is 0.75, with an underflow solids concentration of 12,000
mg/L. Calculate the area required for secondary clarification when
the slope of the limiting solids flux line is 0.5 m/h from a plot of
solids flux (kg/m²-h) versus solids concentration (kg/m³). The set-
tling velocity of the solids at the MLSS concentration of 6500 mg/L
is 0.7 m/h.
Transcribed Image Text:10.10 A wastewater treatment plant consists of a primary clarifier and an activated sludge reactor (with recycle) followed by a secondary clarifier. The average inflow of wastewater to the primary clarifier is 14,500 m³/day with a BOD, of 250 mg/L and suspended solids concentration of 300 mg/L. The recirculation ratio in the secondary system is 0.75, with an underflow solids concentration of 12,000 mg/L. Calculate the area required for secondary clarification when the slope of the limiting solids flux line is 0.5 m/h from a plot of solids flux (kg/m²-h) versus solids concentration (kg/m³). The set- tling velocity of the solids at the MLSS concentration of 6500 mg/L is 0.7 m/h.
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