Feed (F), 100 mol/s A feed (F) containing a solute is contacted with a solyent (S) in an ideal stage as shown in the diagram below. Only the solute transfers Raffinate (Rs), Xout Xin 0.3 into the solvent. The flow rates of all the streams are shown on a Extractor Product( R), Yout solute free basis and indicated by the subscript S. The compositions of the streams are expressed on a mole ratio basis. The extract leaving the contactor is divided into two equal parts, one part collected as the product (P) and the other stream is recycled to join the solvent. The equilibrium relationship is Y* = 2X. The product flow rate (P, ) and composition (Yout ) are Solvent (S,), 100mol/s Xin " 0.0 Extractor Recycle a. Ps = 50 mol/s, Y = 0.3 out = 0.2 out b. P = 100 mol/s, Y Ps = 200 mol/s, Y, P. = 100 mol/s, Y, C. = 0.1 out d. = 0.4 S out

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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100%
Feed (Fs), 100 mol/s
A feed (F) containing a solute is contacted with a solyent (S) in an
ideal stage as shown in the diagram below. Only the solute transfers
Raffinate (Rs), Xout
Xin = 0.3
into the solvent. The flow rates of all the streams are shown on a
Extractor
Product( R), Yout
solute free basis and indicated by the subscript S. The compositions
of the streams are expressed on a mole ratio basis. The extract
leaving the contactor is divided into two equal parts, one part
collected as the product (P) and the other stream is recycled to join
the solvent. The equilibrium relationship is Y* = 2X. The product flow
rate (P, ) and composition (Yout ) are
Solvent (S, ), 100mol/s
Xin = 0.0
Extractor Recycle
Ps = 50 mol/s, Yut = 0.3
b. P = 100 mol/s, Y = 0.2
= 0.1
a.
%3D
%3D
out
Ps = 200 mol/s, Y,
d. P. = 100 mol/s, Y
out
= 0.4
out
S
Transcribed Image Text:Feed (Fs), 100 mol/s A feed (F) containing a solute is contacted with a solyent (S) in an ideal stage as shown in the diagram below. Only the solute transfers Raffinate (Rs), Xout Xin = 0.3 into the solvent. The flow rates of all the streams are shown on a Extractor Product( R), Yout solute free basis and indicated by the subscript S. The compositions of the streams are expressed on a mole ratio basis. The extract leaving the contactor is divided into two equal parts, one part collected as the product (P) and the other stream is recycled to join the solvent. The equilibrium relationship is Y* = 2X. The product flow rate (P, ) and composition (Yout ) are Solvent (S, ), 100mol/s Xin = 0.0 Extractor Recycle Ps = 50 mol/s, Yut = 0.3 b. P = 100 mol/s, Y = 0.2 = 0.1 a. %3D %3D out Ps = 200 mol/s, Y, d. P. = 100 mol/s, Y out = 0.4 out S
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