A vinyl [E = 2.70 GPa; v = 0.43] block with width b = 50 mm, depth d = 100 mm, and height h = 270 mm rests on a smooth rigid base. A load P is applied to a rigid plate that rests on top of the block. Calculate the change in the depth dimension d of the block after a load of P= 120 kN is applied. Rigid plate Width b Depth d Height h Rigid base
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- A vinyl [E = 2.80 GPa; v = 0.43] block with width b = 40 mm, depth d = 80 mm, and height h = 210 mm rests on a smooth rigid base. A load P is applied to a rigid plate that rests on top of the block. Calculate the change in the depth dimension d of the block after a load of P = 60 kN is applied. Rigid plate Answer: Ad = i Width b P Depth d Height h Rigid base mmA vinyl (E-2.70 GPa; v=0.43] block with width b = 50 mm, depth d = 100 mm, and height h = 270 mm rests on a smooth rigid base. A load P is applied to a rigid plate that rests on top of the block. Calculate the change in the depth dimension d of the block after a load of P= 120 kN is applied. Answer: Ad = i mmHomework 8: A (20°C) a rigid beam in placed upon the rods shown in figure: 1) Determine the magnitude of uniformly distributed load w (kN/m) so that beam remains horizontal when temperature of steel becomes to (100°C). 2) Find the stress developed in each rod. Steel A, = 1000mm², as = 12 * 10-6 , E, = 200GPA, L = 500mm %3D %3D Aluminum Aal 1500mm2, aal = 23 * 10-6 , Eal = 70GPA, L = 300mm %3| Rigid beam w (kN /m) A C steel Aluminum 3m 3m
- The two wooden boards shown in the figure are connected by a 0.5 in. diameter bolt. Washers are installed under the head of the bolt and under the nut. The washer dimensions are D 2 in. and d 5/8 in. The nut is tightened to cause a tensile stress of 9,000 psi in the bolt. Determine the bearing stress MPa between the washer and the woodShown is a copper bar which has a diameter of 10 mm and loaded by tensile loadP = 0.0137 MN The maximum shear stress in the bar is approximately: Match each item to a choice: TmaxThe wooden beam shown is made by gluing together planks as shown. 8 kN/m Glue 80 mm A B 80 mm - NA 6 m 80 mm 160 mm Determine the maximum shear stress in the glue in kPa. (2 decimals)
- The rubber band given below is subjected to the following tensile loading. Calculate the minimum thickness of the rubber (tr) and the minimum steel pin diameter (Dpin) so that the structure does not fail. Consider: Allowable tensile strength of the rubber= 20MPa Allowable shear strength of the steel = 200MPa Reflection: 1) How would you solve this problem if a Factor of Safety was given? 2) Are there any other dimensions worth calculating for the rubber belt?GIVEN: Solid alumınum bar shown: 4 in. by4 in. E = 10 x 10° psi oy = 36 ksi 4000 2000 1b 4000 16 B 12' REQ’D: A) Load in each section of the bar (state whether C or T) PAB = Pac PCD = B) Maximum axial stress in the bar. In which section does this occur? C) Final length of the barCalculate the axial deformation of the Brass cylinder section (BC) shown in Figure 8. The cross-sectional areas are Asteel = 80 x 10-³ m² and ABrass = 50 x 10-³ m², and Young's modulus - of steel and brass are 200 MPa and 120 MPa. 100 kN (a) 3.13 mm (b) 7.25 mm (c) 7.5 mm (d) 3.5 mm Steel 50 kN 0.5 m B Brass 0.3 m C Figure 8. A shaft of different diameters Steel 0.5 m Ꭰ 150 kN
- A RECTANGULAR ALUMINUM BLOCK IS 40mm LONG IN THE Y DIRECTION, 20mm WIDE IN THE Z DIRECTION AND 25mm THICK IN THE X DIRECTION. IT IS SUBJECTED TO A TRIAXIAL LOADING CONSISTING OF A UNIFORMLY DISTRIBUTED FORCE OF Px=3 (COMPRESSION), Py=6 (TENSION) AND Pz=9 (COMPRESSION) IN THE X, Y AND Z DIRECTIONS RESPECTIVELY. IF THE POISSON’S RATIO = 1/4 & E = 70 GPa, DETERMINE THE STRAINS IN THE X, Y AND Z DIRECTIONS. ALSO DETRMINE A SINGLE DISTRIBUTED FORCE IN THE Y DIRECTION THE WOULD PRODUCE THE SAME X DEFORMATION AS THE ORIGINAL.1. Shown is a composite plate joined together by rivets. The components consist of two tension bar plates that is % X 4 inch and riveted together by two splice plates which is 0.8 X 6 inch. Each rivet has a diameter of 25.4 mm. Considering that the allowable stress for the tension bar plates and splice plates is o=20.0 ksi, the allowable shear stress for the rivets is o=25.0 ksi and the allowable bearing stress on the rivets and splice plates is o=25.0 ksi. What will be the maximum permissible load P such that none of the allowable stresses will be exceeded? Splice Plates a-0.75 in Bar Lc =0.80 in. Bar P d = 1.0 in. b=4.0 in. Rivets 'e = 6.0 in.1. Determine the nominal load P that will cause failure of the beam shown below. As part of your solution, include sketches of the distribution of strain, the actual distribution of stress, and the equivalent rectangular stress block distribution of stress when appropriate. Reinforcing bars are 4-#7 bars. Material strengths are f. 5.5 ksi and f, = 60 ksi. You may ignore the beam self- weight for this problem. %3D 24 in.! 3 in. 21 in. C A 16 ft 16 ft