Net Cumulative Yardage 5000 4000 3000 2000 1000 -1000 -2000 0 -3000 -4000 -5000 08.0 ○ 9.2 0 O None of these. O 6.0 ○ 9.4 5.0 -3,000 1,500 Given the Mass Haul Diagram above and the following information: • Excavation Cost: $4.00/cu. yd. • Borrow Cost: $3.25/cu. yd. • Overhaul Cost: $1.25/sta*cu. yd. • Free Haul Limit: 600 ft. Compute the limit of economic haul: 2,100 0 5 6.0 8.0 3,500 10 7.1 2,100 -1,100- Stations 15 7.0 8.0 6.0 0 20 1,500 750 25

Net Cumulative Yardage 5000 4000 3000 2000 1000 -1000 -2000 0 -3000 -4000 -5000 08.0 ○ 9.2 0 O None of these. O 6.0 ○ 9.4 5.0 -3,000 1,500 Given the Mass Haul Diagram above and the following information: • Excavation Cost: $4.00/cu. yd. • Borrow Cost: $3.25/cu. yd. • Overhaul Cost: $1.25/sta*cu. yd. • Free Haul Limit: 600 ft. Compute the limit of economic haul: 2,100 0 5 6.0 8.0 3,500 10 7.1 2,100 -1,100- Stations 15 7.0 8.0 6.0 0 20 1,500 750 25

Fundamentals Of Construction Estimating

4th Edition

ISBN:9781337399395

Author:Pratt, David J.

Publisher:Pratt, David J.

Chapter16: Budget Estimating

Section: Chapter Questions

Problem 4RQ: Prepare a typical bay estimate based on the following information: a. Bay size of 350 feet and a...

See similar textbooks

Related questions

Q: A project consists of replacing the truck on an existing existing roadroad line involving 3000 feet…

A: Float of activity Float, also known as Slack (float), is the length of time an activity, network…

Q: The cost of building usually includes all of the following except a. any renovating or remodeling…

Concept explainers

Evaluation of Transportation Projects

Civil engineers undertake a variety of projects related to construction. Building construction projects, structural projects, highway, road construction projects, transportation projects, etc. Transportation projects are related to public constructions that focus to build new connectivity in public transportation. To improve and maintain existing transport facilities also falls under the domain of transportation projects. Some of its objectives include planning, evaluation, designing, development, finance, construction, reconstruction, demolition, rehabilitation, improvement, acquisition, operation, and maintenance. As per the law, all transport projects are authorized to the construction firm that permits them to change the land area meant for public use.

Question

Net Cumulative Yardage
●
5000
4000
3000
2000
C
1000
-1000
-2000
-3000
-4000
-5000
O 8.0
Compute the limit of economic haul:
O None of these.
9.2
5.0
Given the Mass Haul Diagram above and the following information:
Excavation Cost: $4.00/cu. yd.
Borrow Cost: $3.25/cu. yd.
Overhaul Cost: $1.25/sta*cu. yd.
Free Haul Limit: 600 ft.
6.0
-3,000
9.4
1,500
10
5
2,100
Mass Diagram
6.0
8.0
10
3,500
+
7.1
2,100
1,100
Stations
15
7.0
8.0
6.0
20
1,500
750
25

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Introduction and given data

VIEW

Step 2: Limit of economic haul

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 None of these. 11.7 6.0 O 8.0 5.0 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.25/cu. yd. Borrow Cost: $4.50/cu. yd. Overhaul Cost: $0.75/sta*cu. yd. Free Haul Limit: 600 ft. Compute the limit of economic haul: O 12.0 -3,000 1,500 5 2,100 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 $10,590.00 Compute the total overhaul cost: O None of these. Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $3.75/cu.yd. Overhaul Cost: $1.50/sta*cu. yd. ● Free Haul Limit: 600 ft. O $1,590.00 5.0 O $600.00 -3,000 O $990.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 + 7.1 2,100 1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Net Cumulative Yardage ● 5000 ● 4000 3000 2000 1000 -1000 -2000 -3000 -4000 -5000 0 O $34,000.00 Compute the total excavation cost: $10,000.00 Given the Mass Haul Diagram above and the following information: Excavation Cost: $4.00/cu. yd. Borrow Cost: $4.25/cu. yd. Overhaul Cost: $1.25/sta*cu. yd. Free Haul Limit: 600 ft. $32,000.00 5.0 None of these. -3,000 O $26,000.00 1,500 5 2,100 Mass Diagram 6.0 8.0 10 3,500 7.1 2,100 -1,100 Stations 15 7.0 8.0 6.0 20 1,500 750 25
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2.100 7.0 2000 8.0 1,500 1,500 8.0 ------ 1000 -1,100 - 7.1 6.0 750 5.0 0. -1000 3-2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total cost in borrow to the nearest dollar? O $0 O $2,625 $2,813 $5,625 O Non Net Cumulative Yardage
I Net Cumulative Yardage 5000 ● 4000 3000 2000 1000 0 -1000 -2000 -3000 -4000 -5000 0 O $28,875.00 O $47,812.50 4,500 Compute the total borrow costs: O $35,062.50 5.0 O $12,750.00 None of the above -1,500 0 5 --2500 Given the Mass Haul Diagram above and the following information: Excavation Cost: $3.50/cu. yd. Borrow Cost: $4.25/cu. yd. Overhaul Cost: $1.50/sta*cu. yd. Free Haul Limit: 500 ft. 8.0 5.0 16.25 -3,750 10 Stations -1,500 15 5.0 8.0 6.6 20 -750 -1,500 -3,000 25
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 g t--------- 6.0 8.0 O 1000 1,100 - 7.1 750 5.0 TO -1000 3-2000 -3000 -3,000 ´ -4000 -5000 5 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total excavation cost to the nearest dollar? $30,000 O $28,000 $25,375 $20,250 O None of the above Net Cumulative Yardage
The following net accumulations were calculated. The free haul area begins at station 4+30 and continues to 14+30. If the overhaul is charged at $10/yd³ station, what is the total overhaul cost ($)? Round to the nearest cent. from station to station net accumulation, yd³ 2+60 3+00 3.85 3+00 4+00 5.85 4+00 4+30 8.35 Response Feedback: 10x8.35x0.9281
Q1) For the following portion of mass haul diagram (each station is 50 m) answer the following questions: Station 4+00 7+00 6+00 5+00 3+00 2+00 1+00 0+00 -100 200 300 400 500 600 -700 -800 A) If the free haul distance =150 m, find the total cost within the free haul distance if the cost of excavation and transporting up to 150 m = 0.5 JD/ m? B) Find the limit of economical haul distance if the cost transporting is 0.1 JD/ m' for each 30 m beyond the first 150 m? C) Find the volume of waste and borrow materials? D) On the figure above specify the following: · Free haul distance and volume • Limit of economical haul distance and the overhaul volume • The waste and borrow material portion comulative volume m'
8-6. Determine the haul equation constants a and b for the following data. Average haul speed, mi/h Round-trip distance, mi/trip "Arip 4%-9 10 0.9 20 2.9 25 4.0 29 5.5 30 6.0 35 8.0 39 10.0 40 11.0 45 15.5 50 28.0
Given the following Mass-Haul Diagram: Mass Diagram 5000 4000 3,500 3000 2,100 6.0 2,100 7.0 2000 8.0 1,500 1,500 8.0 ----- 1000 1,100 7.1 6.0 750 5.0 0. -1000 -2000 -3000 -3,000 -4000 -5000 10 15 20 25 Stations Limit of free haul = 600 ft Price of excavation = $3.50 Price of borrow = $3.75 Overhaul = $1.50 What is the total quantity of waste in cubic yards? O 2100 O 1500 400 O 750 O None of the above Net Cumulative Yardage
Please, I need to solve the question in less than an hour.
The following are the data of a simple summit mass haul diagram STATION MASS ORDINATE (m3) 0+000 -80 0+500 -130 Mass ordinate at initial point of the limit of free haul distance = +600 Mass ordinate at initial point of the economical haul distance = +200 Limit of Economic Haul = 450m Cost of Haul = P120.00 per cubic meter per meter station a. Determine the volume of borrow and its overhaul volume. b. Determine the length of overhaul if the cost of hauling is 00