A vertical curve is designed to join a +4% grade with a -2% grade. Assume that the stopping sight distance is 600 ft., the driver's eye height above the roadway surface is 3.5 ft., and the height of an object in the road to be avoided by stopping is 3 ft. Determine the minimum design length of the vertical curve.
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- A vertical curve links between -3% & -8% grades, the allowed speed on the curve is 80 kmph and the elevation of the point of intersection is equal to 2009 Calculate the elevation of the beginning and end points of the curve?An equal-tangent crest vertical curve is 1100 ft long and connects a +2.5% and a -1.5% grade. If the design speed of the roadway is 85 mi/h, determine the length of curve, does this curve have adequate passing sight distance?A-1.7% grade intersects a 3.6% grade on a highway with a design speed of 55 mph. What is the length of the curve in ft required? (Assume provisions are to be made for minimum stopping sight distance).
- Highway Engineering: You are designing a highway to AASHTO guidelines on rolling terrain where the design speed will be 65 mi/h. At one section, a +1.25% grade and a -2.25% grade must be connected with an equal-tangent vertical curve. Determine the SSD given the reaction time of 2.5 sec and deceleration of 3.4 m/s^2. Determine also the minimum length of curve.An equal tangent vertical curve is intended to connect grades of 3% and -3.2%. If this curve is to be a part of a highway designed with a speed limit of 70mph, determine the minimum length (ft) of the vertical curve. Use exact solution (do not use the table)The minimum simple curve radius you recommended for a highway with design speed (96) Km / hr, super elevation (5.50 percent and f = 0.11, is: O 493.799 m O 439.799 m O 339.970 m O 440.700 m 430.900 ft / sec.
- A sag vertical curve connects a -1.5 percent grade with a +2.5 percent grade on a rural arterial highway. If the criterion selected for design is the minimum stopping sight distance, and the design speed of the highway is 70 mi/h, compute the elevation of the curve at 100-ft stations if the grades intersect at station (475 +00) at an elevation of 300 ft. Use L = KA to find minimum curve length for this problem.Note: Don't copy from other websites.asap 15 minutes
- A +8 percent grade intersects with a -2 percent grade at station (535 + 24.25) at an elevation of 300 ft. (a) If the design speed is 45 mi/h, determine the minimum length (in ft) of vertical curve using the rate of vertical curvature. (Assume the stopping sight distance is less than the length of the curve.) 610 ft (b) Using the length found in part (a), find the stations and elevations (in ft) of the BVC and EVC and the elevation (in ft) of each 100 ft station. (In the table below, the first row corresponds to the BVC and the last row corresponds to the EVC. Round your elevations to at least one decimal place.) Station Elevation (ft) 532 + 19.25 275.6 533 + 00 306.1 534 + 00 535 + 00 299.7 536 + 00 537 + 00 538 + 00 538 + 29.25 293.9 (c) Using the length found in part (a), find the station and elevation (in ft) of the highpoint. station elevation ftA vertical curve is to be constructed between a 2.5% grade and a -3.5% grade. The required sight distance is 305m. The dangerous object is considered to be on the pavement surface, and the driver's eye level is at 1.05m above the pavement surface. Determine the length of the vertical curve that will satisfy the sight distance requirement.Please correct answer