### Problem StatementBar ABC is rigid and rotates freely about point B. The loads consist of a point load and a uniform temperature change in both bars CD and EF. Determine the temperature change (ΔT) at which points A and E first come into contact. Report your answer rounded to the nearest degree.### Diagram ExplanationThe diagram shows a setup where bar ABC is horizontal and supported at point B. It is subject to a 14 kips (14,000 pounds) load at point C. Two vertical bars, CD and EF, connect at points C and E respectively. **Bar CD:**- Sectional Area (\(A_{CD}\)): 1.5 in²- Young's Modulus (\(E_{CD}\)): 29,000 ksi- Coefficient of Thermal Expansion (\(\alpha_{CD}\)): \(6.5 \times 10^{-6}\) 1/°F- Length (\(L_{CD}\)): 150 in**Bar EF:**- Sectional Area (\(A_{EF}\)): 2.0 in²- Young's Modulus (\(E_{EF}\)): 12,000 ksi- Coefficient of Thermal Expansion (\(\alpha_{EF}\)): \(13.5 \times 10^{-6}\) 1/°F- Length (\(L_{EF}\)): 50 in### Initial Conditions- The initial gap between points A and E is 0.11 inches.- Bar ABC measures 300 inches in total, with 100 inches spacing between each point (A to B, B to C, and C to D).### Axes and Orientation- The vertical axis is labeled as Y.- The horizontal axis into the paper is labeled as Z.The problem involves calculating the temperature change required for thermal expansion in bars CD and EF such that points A and E touch.

Answered: Image /qna-images/answer/ecab8d97-d50d-4f60-a9f8-7d819f3f6234.jpg

a uniform temperature change in both bars CD and EF. Determine the temperature change (AT) at which points A and E first come into contact. Report your answer rounded to the nearest degree. 100 in initial gap = 0.11 in I T E A AEF 100 in = 2.0 in² EEF = 12,000 ksi EF = 13.5 x 10-6 1/°F LEF = 50 in B 14 k 100 in C ACD ECD = 1.5 in² Y = 29,000 ksi acD = 6.5 x 10-6 1/°F LCD = 150 in Z

a uniform temperature change in both bars CD and EF. Determine the temperature change (AT) at which points A and E first come into contact. Report your answer rounded to the nearest degree. 100 in initial gap = 0.11 in I T E A AEF 100 in = 2.0 in² EEF = 12,000 ksi EF = 13.5 x 10-6 1/°F LEF = 50 in B 14 k 100 in C ACD ECD = 1.5 in² Y = 29,000 ksi acD = 6.5 x 10-6 1/°F LCD = 150 in Z

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)

5th Edition

ISBN:9781305084766

Author:Saeed Moaveni

Publisher:Saeed Moaveni

Chapter12: Electric Current And Related Variables In Engineering

Section12.2: Electrical Circuits And Components

Problem 6BYG

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